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a)3.(x-2)+120=240
3.(x-2)=240-120
3.(x-2)=120
x-2=120:3
x-2=40
x=40+2
x=42
tớ xin lỗi,tớ chỉ giải được mỗi câu a thôi
\(\left\{240-\left[76-\left(9-3\right)^2\right]\right\}\div50=\left\{240-\left[76-6^2\right]\right\}\div50=\left\{240-\left[76-36\right]\right\}\div50\)
\(=\left\{240-40\right\}\div50=200\div50=4\)
Tìm x :
\(\left(2+x\right)\div5=6\)
\(2+x=6.5\)
\(2+x=30\)
\(x=30-2\)
\(x=28\)
\(2+x\div5=6\)
\(x\div5=6-2\)
\(x\div5=4\)
\(x=4.5\)
\(x=20\)
So sánh :
a) Ta có : \(125^{80}=\left(5^3\right)^{80}=5^{240}\)
\(25^{118}=\left(5^2\right)^{118}=5^{236}\)
mà \(240>236\)
\(\Rightarrow5^{240}>5^{236}\)
\(\Rightarrow125^{80}>25^{118}\)
b) Ta có : \(2^{161}>2^{160}=\left(2^4\right)^{40}=16^{40}>13^{40}\)
\(\Rightarrow2^{161}>13^{40}\)
2 mũ 6 x bằng 6
2 mũ 5 trừ 2 bằng 30 x = 5
x bằng 12
x bằng 4
x= 4
\(2^x=64\Leftrightarrow2^x=2^6\Leftrightarrow x=6\)
\(2^x-2=30\Leftrightarrow2^x=32\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)
\(18:\left(x-6\right)=3\Leftrightarrow x-6=6\Leftrightarrow x=6+6=12\)
\(3^x-1=80\Leftrightarrow3^x=81\Leftrightarrow3^x=3^4\Leftrightarrow x=4\)
\(240:\left(2x-4\right)=60\Leftrightarrow2x-4=4\Leftrightarrow2x=8\Leftrightarrow x=4\)
\(143-5^{3-x}=3^3\times2^0\Leftrightarrow143-5^{3-x}=27\times1\)
\(\Leftrightarrow143-5^{3-x}=27\Leftrightarrow5^{3-x}=143-27=116\)
mà \(5^{3-x}\ne116\Leftrightarrow x\in\varnothing\)
Vậy: \(x\in\varnothing\)
Nhớ k cho mình nhé! Thank you!!!
a) ta có: 4(x+32)-5=55 nên 4(x+32)=60, nên x+32=60/4=15
Mà 32=9 nên x=4
b) ta có 7(x+52)=210 nên x+52=30 . x+25=30 nên x=5
a) \(2^2.3^{3x}-27^x=9^5\)
\(4.3^{3x}-\left(3^3\right)^x=\left(3^2\right)^5\)
\(4.3^{3x}-3^{3x}=3^{10}\)
\(3^{3x}\left(4-1\right)=3^{10}\)
\(3^{3x}.3=3^{10}\)
\(3^{3x+1}=3^{10}\)
3x + 1 = 10
3x = 9
x = 3.
b. \(5.3^x=135\)
\(3^x=27\)
\(3^x=3^3\)
x = 3.
c. \(5^x.5^4=5^{20}\)
\(5^{x+4}=5^{20}\)
x + 4 = 20
x = 16
Bài 1 :
\(7^5.3^4=16807.81=1361367\)
Bài 2 :
a) Ta có :
\(40=2^3.5\)
\(20=2^2.5\)
Thừa số nguyên tố chung là : 2 ; 5
=> UCLN ( 40 ; 20 ) = \(2^2.5=20\)
Vậy UCLN ( 40 ; 20 ) = \(20\)
b)Ta có :
\(100=2^2.5^2\)
\(240=2^5.3.5\)
Thừa số nguyên tố chung là : 2 ; 5
=> UCLN ( 100 ; 240 ) = \(2^2.5=20\)
Vậy UCLN ( 100 ; 240 ) = 20
a) (x-51)=2.8+20 b) 4.(x-3) = 49-1 c) 2x-49=5.27 d) 9.(x+4)-25=5.4
x-51 =16+20 4.(x-30)=48 2x-49=135 9.(x+4)-25=20
x-51 =36 x-30=48:4 2x =135+49 9.(x+4) =20+25
x = 36+51 x-30= 12 2x =184 9.(x+4) =45
x = 87 x =12+30 x=42 x =184:2 x= 92 x+4 =45:9
x+4 =5
x =5-4 x=1
\(240:\left(x-5\right)=2^2.5^2-20\)
\(240:\left(x-5\right)=80\)
\(x-5=240:80\)
\(x-5=3\)
\(x=8\)
\(240:\left(x-5\right)=2^2.5^2-20\)
\(240:\left(x-5\right)=4.25-20\)
\(240:\left(x-5\right)=100-20\)
\(240:\left(x-5\right)=80\)
\(x-5=240:80\)
\(x-5=3\)
\(x=3+5\)
\(x=8\)