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a) tận cùng là 0
b) tận cùng là 5
c) tận cùng là 6
d) tận cùng là 1
e) tận cùng là 0
g) tận cùng là 5
TL:
8/15 x 5/6 = 40/90 = 4/9
41/20 x 3/4 = 123/80
(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43
HT
\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)
\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)
\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)
/HT\
a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)
= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)
= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)
b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)
= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)
\(a,\frac{1313}{2828}+x=\frac{2323}{4646}\)
\(\frac{13}{28}+x=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{13}{28}=\frac{1}{28}\)
\(b,\frac{5}{7}+\frac{x}{35}=\frac{4}{5}\)
\(\frac{x}{35}=\frac{4}{5}-\frac{5}{7}=\frac{3}{35}\)
\(\Rightarrow x=3\)
\(c,\frac{23}{69}-x=\frac{17}{153}\)
\(\frac{1}{3}-x=\frac{1}{9}\)
\(x=\frac{1}{3}-\frac{1}{9}=\frac{2}{9}\)
\(a,\frac{1313}{2828}+x=\frac{2323}{4646}\)
\(\frac{13}{28}+x=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{13}{28}=\frac{1}{28}\)
\(b,\frac{5}{7}+\frac{x}{35}=\frac{4}{5}\)
\(\frac{x}{35}=\frac{4}{5}-\frac{5}{7}=\frac{3}{35}\)
\(\Rightarrow x=3\)
\(c,\frac{23}{69}-x=\frac{17}{153}\)
\(x=\frac{23}{69}-\frac{17}{153}=\frac{2}{9}\)
P/s : Đúng nha
\(\frac{15}{17}\times\frac{51}{5}< x< \frac{67}{9}+\frac{35}{9}\)
\(\Rightarrow9< x< \frac{102}{9}\)
\(\Rightarrow9< x< 12\)
\(\Rightarrow x=10\)hoặc \(x=11\)
Vậy \(x=10\)hoặc \(x=11\)
a: \(=\dfrac{18}{51}\cdot\dfrac{34}{9}\cdot\dfrac{17}{18}=\dfrac{17}{51}\cdot\dfrac{34}{9}=\dfrac{1}{3}\cdot\dfrac{34}{9}=\dfrac{34}{27}\)
b: \(=\dfrac{21}{32}\cdot\dfrac{4}{7}\cdot25\cdot\dfrac{4}{5}=\dfrac{21}{7}\cdot\dfrac{4}{32}\cdot20=60\cdot\dfrac{1}{8}=\dfrac{15}{2}\)
\(\frac{23}{17}=\frac{x-5}{51}\)
\(\Leftrightarrow\)23x51=(x-5)x17
\(\Leftrightarrow\)1173=(x-5)x17
\(\Leftrightarrow\)x-5=\(\frac{1173}{7}\)
\(\Leftrightarrow\)x=\(\frac{1208}{7}\)
23/17=x-5/51
23x3/17x3=x-5/51
69/51=x-5/51
Suy ra x-5=69
x =69+5
x =74