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\(\frac{11}{1.4}+\frac{11}{4.7}+...+\frac{11}{100.103}\)
\(=\frac{11}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{100.103}\right)\)
\(=\frac{11}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{100}-\frac{1}{101}\right)\)
\(=\frac{11}{3}\left(1-\frac{1}{103}\right)\)
Tự tính
\(\frac{11}{1.4}+\frac{11}{4.7}+...+\frac{11}{100.103}\)
= \(\frac{11}{3}.\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{100.103}\right)\)
= \(\frac{11}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{100}-\frac{1}{103}\right)\)
= \(\frac{11}{3}.\left(1-\frac{1}{103}\right)\)
= \(\frac{11}{3}.\frac{102}{103}\)
= \(\frac{374}{103}\)
a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{55}{24}\)
\(\frac{1}{3}.\frac{1}{x}+\left(\frac{1}{x}+1\right).\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\left(\frac{1}{x}+\frac{x}{x}\right).\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{1+x}{x}.\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{2\left(1+x\right)}{5x}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{2+2x}{5x}=\frac{9}{5}\)
\(\frac{5}{15x}+\frac{6+6x}{15x}=\frac{9}{5}\)
\(\Rightarrow\frac{5+6+6x}{15x}=\frac{3.9x}{15x}\)
\(\Rightarrow\frac{11+6x}{15x}=\frac{27x}{15x}\)
\(\Rightarrow11+6x=27x\)
\(\Rightarrow21x=11\)
\(\Rightarrow x=\frac{11}{21}\)
Vậy \(x=\frac{11}{21}\)
_Hok tốt_
Ta có : 2 + 4 + 6 + 8 +...+ 2.x = 2450
=> 2. ( 1 + 2 + 3 + 4 + ... + x ) = 2450
=> 1 + 2 + 3 + 4 + ... + x = 1225
=> x . ( x + 1 ) : 2 = 1225
=> x . ( x + 1 ) = 2450 = 49 . 50
=> x = 49
Nhưng bạn ơi X là số chẵn đó