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2-1.2n+4.2n=9.25
=>2n-1+22.2n=9.25
=>2n-1+2n+2=9.25
=>2n-1.(23+1)=9.25
=>2n-1.9=9.25
=>2n-1=25
=>n-1=5=>n=6
Ta có: \(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot2^{-1}+2^n\cdot2^2=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\left(2^{-1}+2^2\right)=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot2^5\)
\(\Leftrightarrow2^n=9\cdot2^5:\dfrac{9}{2}=2^5\cdot9\cdot\dfrac{2}{9}=2^6\)
hay n=6
Vậy: n=6
a) \(\frac{1}{9}.27^n=3^n\)
\(=>\frac{27^n}{9}=3^n\)
\(=>3^n=3^n=>n=1\)
b) \(2^{-1}.2^n+4.2^n=9.2^5\)
\(=>2^{n-1}.2^2.2^n=9.2^5\)
\(=>2^{n-1}.2^{2+n}=9.2^5\)
\(=>2^{2n+1}=9.5^2\)
\(=>n=\)
Câu b đề sai hay sao ấy số xấu lắm
2^-1.2^x+4.2^x=9.2^5
0,5.2^x+4.2^x=288
2^x.(4+0,5)=288
2^x.4,5=288
2^x=288:4,5
2^x=64
2^x=2^6
=) x=6
\(2^{-1}.2^x+4.2^x=9.2^5\)
\(\frac{1}{2}.2^x+4.2^x=9.2^5\)
\(2^x\left(\frac{1}{2}+4\right)=9.2^5\)
\(2^x.\frac{9}{2}=288\)
\(2^x=288:\frac{9}{2}\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
1/2*2x+4*2x=9*25
(1/2+4)*2x=225
9/2*2x=225
2x=225:9/2
2x=50
=>x\(\in\phi\)
a, \(3^{-2}.3^4.3^x=3^7\)
\(\Rightarrow3^{-2+4+x}=3^7\)
\(\Rightarrow3^{2+x}=3^7\)
Vì \(3\ne\pm1;3\ne0\) nên \(2+x=7\Rightarrow x=5\)
b, \(2^{-1}.2^x+4.2^x=9.2^5\)
\(\Rightarrow2^x\left(2^{-1}+4\right)=288\)
\(\Rightarrow2^x.4,5=288\Rightarrow2^x=64=2^6\)
Vì \(2\ne\pm1;2\ne0\) nên \(x=6\)
Chúc bạn học tốt!!!
\(\frac{1}{2}.2^x+4.2^x=9.2^5\)
\(\Rightarrow\)2x(\(\frac{1}{2}+4\))=9.25
\(\Rightarrow\)\(\frac{9}{2}.2^x=9.2^5\)
\(\Rightarrow9.2^{x-1}=9.2^5\)
\(\Rightarrow2^{x-1}=2^5\)
\(\Rightarrow\)x-1=5
\(\Rightarrow\)x=6(tm)
Vậy x=6