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c, 64 * 25 + 35 * 25 + 25
= 64 * 25 + 35 * 25 + 25 * 1
= (64 + 35 + 1) * 25
= 100 * 25
= 2500
a,24.57+43.24
=24.(57+43)
=24.100
=2400
b,12.19+12
=12.(19+1)
=12.20
=12.10.2
=120.2
=240
c,43.27+93.43+57.61+59.57
=43.(27+93)+57.(61+59)
=43.120+57.120
=120.(43+57)
=120.100
=12000
d,64.6+81.4+17.6
=64.6+27.3.2.2+17.6
=64.6+54.6+17.6
=(64+54+17).6
=135.6
=810
a) 24 . 57 + 43 . 24
= 24 . (57 + 43)
= 24 . 100
= 2400
b) 12 . 19 + 12
= 12 . (19 + 1)
= 12 . 20
=240
c) 43 . 27 + 93 . 43 + 57 . 61 +59 . 57
= 43 . ( 27 + 93) + 57 . (61 + 59)
= 43 . 120 + 57 . 120
= 120 . (43 + 57)
= 120 . 100
= 12000
= \(\left(1+\frac{1}{2}\right)+\left(1+\frac{1}{6}\right)+\left(1+\frac{1}{12}\right)+....+\left(1+\frac{1}{90}\right)\)
= \(\left(1+1+1+....+1\right)+\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{90}\right)\)(9 số 1)
= 9 + \(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{9.10}\right)\)
= \(9+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
= \(9+\left(1-\frac{1}{10}\right)=9+\frac{9}{10}=\frac{90}{10}+\frac{9}{10}=\frac{99}{10}\)
17,84 + 21,3 + 8,16 + 3,7
= (17,84 + 8,16) + (21,3 + 3,7)
= 26 + 25
= 51
2,93 + 14 , 57 + 7,07 + 21, 43
= (2,93 + 7,07) + (14,57 + 21,43)
= 10 + 36
= 46