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\(a,\frac{x+15}{x}=\frac{4}{3}\Rightarrow4x=3x+45\Leftrightarrow x=45\)
\(b,\frac{7,5-x}{3,5+x}=\frac{5}{6}\Rightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Rightarrow x=2,5\)
\(c,\frac{x-20}{x-10}=\frac{x+40}{x+70}\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Leftrightarrow x^2+50x-1400=x^2+30x-400\)
\(\Leftrightarrow20x=1000\)
\(\Rightarrow x=50\)
a. \(\frac{\left(x+15\right)}{x}=\frac{4}{3}\Leftrightarrow4x=3\left(x+15\right)\Leftrightarrow4x=3x+45\Leftrightarrow x=45\)
Vậy x=45
b. \(\frac{7,5-x}{3,5+x}=\frac{5}{6}\Leftrightarrow5\left(3,5+x\right)=6\left(7,5-x\right)\Leftrightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Leftrightarrow x=2,5\)
Vậy x=2,5
c. \(\frac{x+20}{x-10}=\frac{x+40}{x+70}\Leftrightarrow\left(x+40\right)\left(x-10\right)=\left(x+20\right)\left(x+70\right)\)
\(\Leftrightarrow x^2+30x-400=x^2+90x+1400\Leftrightarrow-60x=-30\Leftrightarrow x=-30\)
Vậy x=-30
\(a,\left(x+15\right):x=4:3\)
=>\(1+\dfrac{15}{x}=\dfrac{4}{3}\)
=>\(\dfrac{15}{x}=\dfrac{1}{3}\)
=>\(x=3.15=45\)
Vậy x=45
b)\(\dfrac{7,5-x}{3,5+x}=\dfrac{5}{6}\)
\(6\left(7,5-x\right)=5\left(3,5+x\right)\)
=>\(45-6x=17,5+5x\)
=>\(-11x=-27,5\)
=>\(x=2,5\)
Vậy...
c)\(\dfrac{x-20}{x-10}=\dfrac{x+40}{x+70}\)
=>\(\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
=>\(x^2+50x-140=x^2+30x-40\)
=>\(20x=100\)
=>\(x=50\)
Ta có
\(\frac{2}{3}-\frac{19}{5}x=-3,5\)
<=>\(\frac{19}{5}x=\frac{2}{3}+3,5\)
<=>\(\frac{19}{5}x=\frac{25}{6}\)
<=>\(x=\frac{125}{114}\)
Nhớ tick nha
Bài 2:
a:
1: \(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Leftrightarrow\dfrac{a+b}{a}=\dfrac{c+d}{c}\)
hay \(\dfrac{a}{a+b}=\dfrac{c}{c+d}\)
|x-3,5|-3,5=4
|x-3,5|=4+3,5
|x-3,5|=7,5
=>x-3,5=7,5 hoặc x-3,5=-7,5
x=7,5+3,5 x=-7,5+3,5
x=11 x=-4
Vậy x=11 hoặc x=-4
ii: Ta có: 15:4=x:3.5
nên \(x=\dfrac{3.5\cdot15}{4}=\dfrac{105}{8}\)
I x-3,5 I =4+3,5
I x-3,5 I =7,5
*x-3,5=7,5 * x-3,5=-7,5
x=7,5+3,5 x=-7,5+3,5
x=11 x=-4
=>x\(\in\){11;-4}
a) \(\left|x-1,7\right|+\dfrac{1}{2}=23\)
\(\left|x-1,7\right|=22,5\)
\(\Rightarrow x-1,7=\pm22,5\)
\(\Rightarrow x=\left\{24,2;-20,8\right\}\)
b) \(\left|x+\dfrac{4}{15}\right|-\left|3,75\right|=-\left|2,15\right|\)
\(\left|x+\dfrac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\dfrac{4}{15}\right|=1,6\)
\(\Rightarrow x+\dfrac{4}{15}=\pm1,6\)
\(\Rightarrow x=\left\{\dfrac{4}{3};-\dfrac{28}{15}\right\}\)
TL
x=13,125
HT ( sai thì sorry bn nha )
\(15\div4=x\div3,5\)
\(x\div3,5=15\div4\)
\(\text{Rùi đó bạn học lớp bảy bạn tự tính đi nhé}\)