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a/ 40^20=40^2.10=1600^10
3^30=3^3.10=27^10
vì 1600^10>27^10 nên 40^20>3^30
a) 40^20=(4^2)^10=16^10
30^30=(3^3)^10=27610
Vì 16<27=>16^10<27^10 hay 4^20<3^30
b) mk chịu
c) Đặt A= 1/3+1/3^2+1/3^3+...+1/3^99
=>3A=3( 1/3+1/3^2+1/3^3+...+1/3^99)
=>3A=1+1/3+1/3^2+...+1/3^98
=>3A-A=(1+1/3+1/3^2+...+1/3^98)-(1/3+1/3^2+1/3^3+...+1/3^99)
=>2A=1-1/3^99
=>A=(1-1/3^99)/2
=>A=1/2 - (1/3^99)/2 < 1/2=>a<1/2
1) x - 36 + 12 = - x+ 10
=> x + x = 10 + 24
=> 2x = 34
=> x = 34/2 = 17
2) (x + 15) - (11 - x) = (-2)2
=> x + 15 - 11 + x = 4
=> 2x = 4 - 4
=> 2x = 0
=> x = 0
3) 40 - 4x2 = (-6)2
=> 40 - 4x2 = 36
=> 4x2 = 40 - 36
=> 4x2 = 4
=> x2 = 1
=> x = \(\pm\)1
4) (-50) + 10x2 = (-25) x |-2|
=> -50 + 10x2 = -50
=> 10x2 = -50 + 50
=> 10x2 = 0
=> x2 = 0
=> x = 0
5) |x + 1| = 2020
=> \(\orbr{\begin{cases}x+1=2020\\x+1=-2020\end{cases}}\)
=> \(\orbr{\begin{cases}x=2019\\x=-2021\end{cases}}\)
6) (x + 1)5 + 8 = 0 (xem lại đề)
7) (-20) + x3 : 16 = -24
=> x3 : 16 = -24 + 20
=> x3 : 16 = -4
=> x3 = -4 . 16
=> x3 = -64 = (-4)3
=> x = -4
9) x14 = x17
=> x14 - x17 = 0
=> x14(1 - x3) = 0
=> \(\orbr{\begin{cases}x^{14}=0\\1-x^3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
10) (-36) + (1 - x)2 = 0
=> (1 - x)2 = 36
=> (1 - x)2 = 62
=> \(\orbr{\begin{cases}1-x=6\\1-x=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=-5\\x=7\end{cases}}\)
a) \(3-\left(\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)
\(=3+\left(\dfrac{6}{7}\right)^0+\dfrac{1}{4}.\dfrac{1}{2}\)
\(=3+1+\dfrac{1}{8}=4+\dfrac{1}{8}\)
\(=\dfrac{33}{8}\)
b) \(64.2^3.\dfrac{1}{32^2}\)
\(=2^6.2^4.\dfrac{1}{32^2}=2^{10}.\dfrac{1}{32^2}\)
\(=\left(2^5\right)^2.\dfrac{1}{32^2}=32^2.\dfrac{1}{32^2}\)
= 1
c) \(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
\(=-8+4+1+1\)
\(=-8+6=-2\)
d) \(2^3+3.\left(\dfrac{1}{2}\right)^0-\left(\dfrac{1}{2}\right)^2.4\left[\left(-2\right)^2:\dfrac{1}{2}\right].8\)
\(=8+3.1-\dfrac{1}{4}.4+\left[4:\dfrac{1}{2}\right].8\)
\(=8+3-1+\left[4.2\right].8\)
\(=8+3-1+8.8\)
\(=10+64=74\)
Chúc bạn học tốt!!
\(A=\left(\frac{21}{5}-\frac{3}{5}\right):\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}:\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}\times\frac{8}{16}\times\frac{10}{9}\)
\(A=\frac{9}{5}\times\frac{8}{8}\times\frac{10}{9}\)
\(A=\frac{72}{40}\times\frac{10}{9}\)
\(A=\frac{8}{4}\times\frac{1}{1}\)
\(A=\frac{8}{9}\)
\(B=\left(1\frac{1}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(2+\frac{14}{16}\right)\)
\(B=\left(\frac{21}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(\frac{32}{16}+\frac{14}{16}\right)\)
\(B=\left(\frac{105}{100}+\frac{36}{100}\right):\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}:\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}\times\frac{25}{84}\times\frac{16}{46}\)
\(B=\frac{141}{4}\times\frac{1}{84}\times\frac{16}{46}\)
\(B=\frac{141}{336}\times\frac{16}{46}\)
\(B=\frac{141}{21}\times\frac{1}{46}\)
\(B=\frac{141}{966}\)
1) 3.(-4)2+2.(-5)-20
= 3.16+(-10)-20
= 48+(-10)-20
= 38-20
= 18
2) 5.(-3)2-14.(-8)+(-40)
= 5.9-(-112)+(-40)
= 45-(-112)+(-40)
= 157+(-40)
= 117
3) 31-[26-(209+35)]
= 31-[26-244]
= 31-[-218]
= 249
Tk mk nhé!Thank you very much!
mk làm câu 3 nha!!!
\(31-\left[26-\left(209+35\right)\right]\)
\(=31-\left[26-209-35\right]\)
\(=31-26+209+35\)
\(=\left(31+209\right)+\left(-26+35\right)\)
\(=240+9\)
\(=249\)
chúc bn học giỏi!@@
hỏi google đi trời mô làm được