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Câu 2:
a: =>-11/12x=-1/6-3/4=-2/12-9/12=-11/12
=>x=1
b: =>x-42=57-x-50=7-x
=>2x=49
hay x=49/2
d: =>x+1=3 hoặc x+1=-3
=>x=2 hoặc x=-4
e: =>2x+3=5 hoặc 2x+3=-5
=>2x=2 hoặc 2x=-8
=>x=1 hoặc x=-4
Nửa chu vi khu đất là:
\(\dfrac{3}{4}+\dfrac{5}{8}=\dfrac{11}{8}\left(km\right)\)
b)Chiều dai hơn chiều rộng là:
\(\dfrac{3}{4}-\dfrac{5}{8}=\dfrac{1}{8}\left(km\right)\)
a)chu vi cua khu dat la
3\4+5\8=11\8(km)
nua chu vi cua khu dat la
11\8/2=11\16(km)
b)chieu dai hon chieu rong la
3\4-5\8=1\8
a)Vì hai góc AOB và góc AOC kề bù
Do đó:AOB+AOC=1800
Vậy:1240+AOC=1800
AOC=560
b) Ta có:\(\widehat{COM}=\widehat{AOC}+\widehat{AOM}\)
Thay số:\(118^0=56^0+\widehat{AOM}\)
\(\Rightarrow\widehat{AOM}=62^0\)
Do đó ta có:\(\widehat{AOM}+\widehat{MOB}=\widehat{AOB}\)
Thay số:\(62^0+\widehat{MOB}=124^0\)
\(\Rightarrow\widehat{MOB}=62^0\)
Vậy:\(\widehat{MOB}=\widehat{AOM}\)
Suy ra Om là tia p/giác của góc AOB
Bài 1 :
a) \(x+2\dfrac{3}{4}=5\dfrac{2}{3}\)
\(x+\dfrac{11}{4}=\dfrac{17}{3}\)
\(x=\dfrac{17}{3}-\dfrac{11}{4}\)
\(x=\dfrac{35}{12}\)
Vậy .........................
b) \(x.3\dfrac{1}{2}=4\dfrac{3}{4}\)
\(x.\dfrac{7}{2}=\dfrac{19}{4}\)
\(x=\dfrac{19}{4}:\dfrac{7}{2}\)
\(x=\dfrac{19}{14}\)
Vậy .................
c) \(x:3\dfrac{1}{2}=4\dfrac{3}{4}\)
\(x:\dfrac{7}{2}=\dfrac{19}{4}\)
\(x=\dfrac{19}{4}.\dfrac{7}{2}\)
\(x=\dfrac{133}{8}\)
Vậy ...................
e) \(x-\dfrac{3}{4}=6.\dfrac{3}{8}\)
\(x-\dfrac{3}{4}=\dfrac{9}{4}\)
\(x=\dfrac{9}{4}+\dfrac{3}{4}\)
\(x=3\)
Vậy .............
f) \(\dfrac{7}{8}:x=3-\dfrac{1}{2}\)
\(\dfrac{7}{8}:x=\dfrac{5}{2}\)
\(x=\dfrac{7}{8}:\dfrac{5}{2}\)
\(x=\dfrac{7}{20}\)
Vậy ................
g) \(x+\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{3}{4}\)
\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}-\dfrac{1}{6}\)
\(x=\dfrac{7}{12}\)
Vậy .................
h) \(x+17,67=100-63,2\)
\(x+17,67=36,8\)
\(x=36,8-17,67\)
\(x=19,13\)
Vậy ................
i) \(x:0,01=10\)
\(x=10.0,01\)
\(x=0,1\)
Vậy ...............
k) \(8,01-x=1,99\)
\(x=8,01-1,99\)
\(x=6,02\)
Vậy ............
l) \(x.0,5=2,2\)
\(x=2,2:0,5\)
\(x=4,4\)
Vậy ............
m) \(x:7,5=3,7+4,1\)
\(x:7,5=7,8\)
\(x=7,8.7,5\)
\(x=58,5\)
Vậy ............
Câu 1:
a: \(=\dfrac{9\left(13+7\right)}{9\left(19-6\right)}=\dfrac{20}{13}\)
b: \(=\dfrac{2}{3}\cdot\dfrac{7+8}{14}=\dfrac{2}{3}\cdot\dfrac{15}{14}=\dfrac{30}{42}=\dfrac{5}{7}\)
Câu 2:
a: \(-\dfrac{5}{6}x+\dfrac{3}{4}=\dfrac{1}{3}\)
nên -5/6x=1/3-3/4=-5/12
hay x=1/2
b: \(\left(5+\dfrac{4}{7}\right):x=13\)
nên 39/7:x=13
hay x=3/7