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`(0,13)/x = 9/42`
`(0,13)/x=3/14`
`0,13 . 14 = 3.x`
`0,52=3x`
`x=13/75`
a. \(\left|x-\frac{11}{12}\right|=0\Rightarrow x-\frac{11}{12}=0\Rightarrow x=\frac{11}{12}\)
b. \(\frac{0,13}{x}=\frac{9}{42}\Leftrightarrow0,13.42=9x\Leftrightarrow5,46=9x\Leftrightarrow x=\frac{91}{150}\)
c. \(\left(x-\frac{2}{3}\right)^3=\left(-\frac{1}{3}\right)^3\Leftrightarrow x-\frac{2}{3}=-\frac{1}{3}\Leftrightarrow x=\frac{1}{3}\)
Bài 2 : \(\left|x-\frac{11}{12}\right|=0\Rightarrow x=\frac{11}{12}\)
b) \(\frac{0,13}{x}=\frac{9}{42}\Rightarrow0,13\cdot42=9x\Rightarrow9x=5,46\Rightarrow x=\frac{91}{150}\)
c) \(\left(x-\frac{2}{3}\right)^3=-\frac{1}{27}=\left(-\frac{1}{3}\right)^3\)
=> \(x-\frac{2}{3}=-\frac{1}{3}\Rightarrow x=-\frac{1}{3}+\frac{2}{3}=\frac{1}{3}\)
Với \(x\le-42,A=-x-x-4-x-9-x-42=-4x-55\)
Do \(x\le-42\Rightarrow-4x-55\ge113\)
Với \(-42< x\le-9,A=-x-x-4-x-9+x+42=-2x+29\)
Do \(-42< x\le-9\Rightarrow113>-2x-29\ge47\)
Với \(-9< x\le-4,A=-x-x-4+x+9+x+42=47\)
Với \(-4< x\le0,A=-x+x+4+x+9+x+42=2x+55\)
Do \(-4< x\le0\Rightarrow47< 2x+54\le55\)
Với \(x>0,A=x+x+4+x+9+x+42=4x+55\ge55\)
Vậy minA = 47 khi \(-9\le x\le-4\)
42 -(2x + 32) + 12 :2 =6
42 - 2x - 32 + 6 = 6
42 - 2x - 32 = 0
42 - 2x = 32
2x = 42 - 32 = 10
x = 5
134 - 2 . {156 - 6.[54 -2.(9+6) ] } x = 86
134 - 2.{ 156 - 6.[54 - 2 . 15 ]} x = 86
134 - 2.{ 156 - 6 . 24} x = 86
134 - 2. 12 .x = 86
134 - 24x = 86
24x = 48
x = 2
\(42-\left(2x+32\right)+12:2=6\)
\(\Rightarrow42-2x-32=0\)
\(\Rightarrow2x=10\)
\(\Rightarrow x=5\)
\(\frac{32-x}{7}=\frac{x-42}{9}\)
=\(\frac{\left(32-x\right)9}{63}=\frac{\left(x-42\right)7}{63}\)
\(\Rightarrow\)\(\left(32-x\right)9=\left(x-42\right)7\)
=\(288-x9=x7-294\)
=\(288+294=x9+x7\)
=\(x=-36\frac{6}{16}\)
=\(x\times16=-582\)
\(x=-582\div16\)
a,\(\frac{32-x}{7}=\frac{x-42}{9}\)
\(\Leftrightarrow9\left(32-x\right)=7\left(x-42\right)\)
\(\Leftrightarrow288-9x-7x-294=0\)
\(\Leftrightarrow9x+7x=288-294\)
\(\Leftrightarrow2x=-6\)
\(\Leftrightarrow x=-3\)
b. \(\left(2x-1\right)^2+\left|x+3\right|=0\)
\(\Leftrightarrow\left|x+3\right|=-4x^2+4x-1\)
\(\left|x+3\right|=x+3\)khi \(x+3\ge0\)hay \(x\ge-3\)
\(\left|x+3\right|=-\left(x+3\right)\)khi \(x+3< 0\)hay \(x< -3\)
với \(x\ge-3\Rightarrow x+3=-4x^2+4x-1\)
\(\Leftrightarrow4x^2-4x+1+x+3=0\)
\(\Leftrightarrow4x^2-3x+4=0\)\(\Leftrightarrow\)vô nghiệm
với \(x< -3\)\(\Rightarrow-x-3=-4x+4-1\)
\(\Leftrightarrow4x^2-4x+1-x-3=0\)
\(\Leftrightarrow4x^2-5x-2=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5+\sqrt{57}}{8}\left(tm\right)\\x=\frac{5-\sqrt{57}}{8}\left(L\right)\end{cases}}\)
Bài 2:
a:
1: \(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Leftrightarrow\dfrac{a+b}{a}=\dfrac{c+d}{c}\)
hay \(\dfrac{a}{a+b}=\dfrac{c}{c+d}\)
A)13-5x=3
5x=13-3
5x=10
x=10:5
x=2
B)2(3x-5)-36=42
2(3x-5) =42+36
2(3x-5) =78
3x-5 =78:2
3x-5 =39
3x =39+5
3x =44
x =44:3
x =44/3
C)27:(x-31)=9
x-31 =27:9
x-31 =3
x =3+31
x =34
Bn k cho mik nha!!!!!
\(Z\subset R\)
\(\sqrt{2013}\in R\)
\(-212\notin N\)
\(0,13\notin I\)
0,1(4)=13/90
0,2(15)=71/330
0,13(2)=119/900
k cho mk nhé!!!!!!!!!!!!!!!!!!!
0,1(4)=0,1+0.0(2)=0,1+1/10*0,(2)=1/10+1/10*0,(1)*2=1/10+1/10*1/9*2=1/10+1/90*2=1/10+1/45=45/450+10/450=55/450=11/90.
câu tiếp theo cũng làm như vậy chỉ thay số thôi..
nếu không biết mình sẽ giải hai câu tieps cho bạn nhé...
\(\frac{0,13}{x}=\frac{9}{42}\)
=> \(\frac{0,13}{x}=\frac{3}{14}\)
=> \(0,13\cdot14=3x\)
=> \(3x=1,82\)
=> \(x\approx0,6\)