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a)Ta có:
\(\dfrac{-3}{7}=\dfrac{\left(-3\right)\cdot111}{7.111}=\dfrac{-333}{7}\)
b)\(15\%=\dfrac{3}{20}=0,15\)
\(5\%=\dfrac{1}{20}=0,05\)
c)\(-5\dfrac{1}{2}=-\dfrac{11}{2}\Rightarrow\)số nghịch đảo của nó là:\(-\dfrac{2}{11}\)
\(\)\(1,3=\dfrac{13}{10}\Rightarrow\)số nghịch đảo của nó là:\(\dfrac{10}{13}\)
\(\dfrac{48}{25}\cdot\dfrac{27}{55}+2\dfrac{4}{9}\cdot\dfrac{14}{33}\)
\(=\dfrac{1296}{1375}+\dfrac{22}{9}\cdot\dfrac{14}{33}\\ =\dfrac{1296}{1375}+\dfrac{28}{27}\\ =\dfrac{34992}{37125}+\dfrac{38500}{37125}\\ =\dfrac{73492}{37125}\)
\(1\dfrac{19}{22}\cdot\left(\dfrac{47}{77}-\dfrac{16}{15}\right)\\ =\dfrac{41}{22}\cdot\dfrac{-527}{1155}\\ =\dfrac{-21607}{25410}\)
\(\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)-\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\\ =\left(\dfrac{307}{99}+\dfrac{37}{99}-\dfrac{1503}{299}\right)-0\\ =\dfrac{344}{99}-\dfrac{1053}{299}\\ =-\dfrac{107}{2277}\)
\(\dfrac{-4}{11}\) = \(\dfrac{x}{22}\) = \(\dfrac{40}{y}\)
\(x\) = -\(\dfrac{4}{11}\).22 = -8
y = 40 :( -\(\dfrac{4}{11}\))
y = - 110
Vậy (\(x\);y) =(-8; -110)
\(\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{y}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{x}{22}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{-4\cdot2}{11\cdot2}=\dfrac{-8}{22}\)
\(\Rightarrow\dfrac{-8}{22}=\dfrac{40}{y}\)
\(\Rightarrow\dfrac{-8}{22}=\dfrac{-8\cdot\left(-5\right)}{22\cdot\left(-5\right)}=\dfrac{40}{-110}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{-8}{22}=\dfrac{40}{-110}\)
\(\Rightarrow\left(x,y\right)=\left(-8;-110\right)\)
Cho S = \(\dfrac{1}{21}\)+ \(\dfrac{1}{22}\)+ ... + \(\dfrac{1}{30}\)
So sánh S với \(\dfrac{1}{3}\)
\(S=\dfrac{1}{21}+\dfrac{1}{22}+...+\dfrac{1}{30}\)
\(S>\dfrac{1}{30}+\dfrac{1}{30}+...+\dfrac{1}{30}=\dfrac{10}{30}=\dfrac{1}{3}\)
=3/7+2/5=15/35+14/35=29/35
=3/7+2/5=15/35+14/35=29/35