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\(-\dfrac{1}{12}+\left(-\dfrac{5}{6}\right)-\dfrac{4}{3}=-\dfrac{1}{12}-\dfrac{5}{6}-\dfrac{4}{3}=-\dfrac{1}{12}-\dfrac{10}{12}-\dfrac{16}{12}=-\dfrac{27}{12}=-\dfrac{9}{4}\)
a: \(=2+\dfrac{13}{19}+\dfrac{8}{21}-\dfrac{13}{19}+\dfrac{7}{2}+\dfrac{13}{21}\)
\(=2+\dfrac{7}{2}+1=3+\dfrac{7}{2}=\dfrac{13}{2}\)
b: \(=\dfrac{11}{25}\left(-192-150\right)=\dfrac{11}{25}\cdot\left(-342\right)=-\dfrac{3762}{25}\)
Sửa đề:\(\frac{\frac{2}{11}-\frac{2}{13}-\frac{2}{19}}{\frac{5}{19}-\frac{5}{11}-\frac{5}{13}}\)
\(=\frac{2.\left(\frac{1}{11}-\frac{1}{13}-\frac{1}{19}\right)}{5.\left(\frac{1}{19}-\frac{1}{11}-\frac{1}{13}\right)}\)
\(=\frac{2}{5}\)
\(\frac{\frac{2}{11}+\frac{2}{13}-\frac{2}{19}}{\frac{5}{19}-\frac{5}{11}-\frac{5}{13}}\)
\(=\frac{\frac{48}{143}-\frac{2}{19}}{\frac{-40}{209}-\frac{5}{13}}\)
\(=\frac{\frac{626}{2717}}{\frac{-1565}{2717}}\)
\(=\frac{626}{-1565}\)
\(=-0,4\)
=43/306:599/105x1473/1820
=1505/61098x1473/1820
=0.01993613035
\(\left(\frac{-24}{11}\right)+\left(\frac{-19}{13}\right)+\frac{2}{11}+\left(\frac{-20}{13}\right)\)
=> \(\left[\left(\frac{-24}{11}\right)+\frac{2}{11}\right]+\left[\left(\frac{-19}{13}\right)+\left(\frac{-20}{13}\right)\right]\)
=> \(\left(\frac{-22}{11}\right)+\left(\frac{-39}{13}\right)\)
=> \(-2+-3=-5\)