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a) ( x2 - 5 )( x + 3 ) = x3 + 3x2 - 5x - 15
b) ( x + 4 )( x - x2 ) = x2 - x3 + 4x - 4x2 = -x3 - 3x2 + 4x
c) ( x2 - 6 )( x + 2 ) + ( x + 3 )( x - x2 ) = x3 + 2x2 - 6x - 12 + x2 - x3 + 3x - 3x2 = -3x - 12 = -3( x + 4 )
d) x( x - y ) - y( x - y ) = ( x - y )( x - y ) = ( x - y )2
e) x2( x + y ) - x( x2 - y ) = x3 + x2y - x3 + xy = x2y + xy = xy( x + 1 )
f) 3x( 12x - 4 ) - 9x( 4x - 3 ) = 36x2 - 12x - 36x2 + 27x = 15x
Bài làm
a) ( x2 - 5 )( x + 3 )
= x3 + 3x2 - 5x - 15
b) ( x + 4 )( x - x2 )
= ( x + 4 ) . x( 1 - x )
= x( x + 4 )( 1 - x )
= x( x - x2 + 4 - 4x )
= x( 4 - x2 - 3x )
= 4x - x3 - 3x2
c) ( x2 - 6 )( x + 2 ) + ( x + 3 )( x - x2 )
= ( x - 3 )( x + 3 )( x + 2 ) + ( x + 3 )( x - x2 )
= ( x + 3 )[ ( x - 3 )( x + 2 ) + ( x - x2 )]
= ( x + 3 ) [ x2 + 2x - 3x - 6 + x2 - x2 ]
= ( x + 3 ) ( x2 - x - 6 )
= x3 - x2 - 6x + 3x2 - 3x - 18
= x3 + 2x2 - 9x - 18
d) x( x - y ) - y( x - y )
= ( x - y )( x - y )
= ( x - y )2
= x2 - 2xy + y
e) x2( x + y ) - x( x2 - y )
= x3 + x2y - x3 + xy
= x2y + xy
f) 3x( 12x - 4 ) - 9x( 4x - 3 )
= 3x . 3( 4x - 1 ) - 9x( 4x - 3 )
= 9x( 4x - 1 ) - 9x( 4x - 3 )
= 9x( 4x - 1 - 4x + 3 )
= 9x . 2
= 18x
1: a) Ta có: \(A=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)
\(=x^2+2x+y^2-2y-2xy+37\)
\(=\left(x^2-2xy+y^2\right)+\left(2x-2y\right)+37\)
\(=\left(x-y\right)^2+2\left(x-y\right)+37\)
\(=7^2+2.7+37\) (Vì \(x-y=7\))
\(=100\)
Vậy \(A=100\)
b) Ta có: \(B=x^2+4y^2-2x+10+4xy-4y\)
\(=\left(x^2+4xy+4y^2\right)-\left(2x+4y\right)+10\)
\(=\left(x+2y\right)^2-2\left(x+2y\right)+10\)
\(=5^2-2.5+10\)
\(=25\)
Vậy \(B=25\)
c) Ta có : \(C=\left(x-y\right)^2\)
\(=x^2-2xy+y^2\)
\(=\left(x^2+y^2\right)-2xy\)
\(=26-2.5\) (Vì \(x^2+y^2=26\) ; \(xy=5\))
\(=16\)
Vậy \(C=16\)
2: a) \(\left(x+y\right)^2-y^2=x^2+2xy+y^2-y^2\)
\(=x^2+2xy\)
\(=x\left(x+2y\right)\) \(\left(dpcm\right)\)
b) \(\left(x^2+y^2\right)^2-2xy^2=\left(x^2-2xy+y^2\right)\left(x^2+2xy+y^2\right)\)
\(=\left(x-y\right)^2\left(x+y\right)^2\) \(\left(dpcm\right)\)
c) \(\left(x+y\right)^2=x^2+2xy+y^2\)
\(=\left(x^2-2xy+y^2\right)+4xy\)
\(=\left(x-y\right)^2+4xy\) \(\left(dpcm\right)\)
Chúc bn học tốt ✔✔✔
a: \(A=2x^2-2xy-y^2+2xy=2x^2-y^2\)
\(=2\cdot\dfrac{4}{9}-\dfrac{1}{9}=\dfrac{7}{9}\)
b: \(B=5x^2-20xy-4y^2+20xy=5x^2-4y^2\)
\(=5\cdot\dfrac{1}{25}-4\cdot\dfrac{1}{4}\)
=1/5-1=-4/5
c \(C=x^3+6x^2+12x+8=\left(x+2\right)^3=\left(-9\right)^3=-729\)
d: \(D=20x^3-10x^2+5x-20x^2+10x+4\)
\(=20x^3-30x^2+15x+4\)
\(=20\cdot5^3-30\cdot5^2+15\cdot2+4=1784\)
https://olm.vn/thanhvien/quynhgiang2k4 à mình quên ghi đề bài là:
rút gọn biểu thức nha
a) \(x^6-y^6=\left(x^3-y^3\right)\left(x^3+y^3\right)\)
b) \(\left(x+y\right)^2-\left(x-y\right)^2=\left(2y\right)\left(2x\right)\)
c) \(\left(3x+1\right)^2-\left(x+1\right)^2=4x\left(2x+1\right)\)
f) \(x^2-2xy+y^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\)
\(d,x^2-10x+25=\left(x-5\right)^2\)
\(e,x^2-x-y^2-y=x^2-y^2-x-y=\left(x-y\right)\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)\)
\(h,xy\left(x+y\right)+yz\left(y+z\right)+xz\left(x+z\right)+2xyz\)
\(=xy\left(x+y\right)+yz\left(y+z\right)+xyz+xz\left(x+z\right)+2xyz+xyz\)
\(=xy\left(x+y\right)+yz\left(y+z+x\right)+xz\left(x+z+y\right)\)
\(=xy\left(x+y\right)+z\left(x+y\right)\left(x+y+z\right)\)
\(=\left(x+y\right)\left(xy+zx+zy+z^2\right)\)
\(=\left(x+y\right)\left(x+z\right)\left(y+z\right)\)
\(g,3\left(x-3\right)\left(x+7\right)+\left(x-4\right)^2+48\)
\(=3\left(x^2+4x-21\right)+\left(x^2-8x+16\right)+48\)
\(=3x^2+12x-63+x^2-8x+64\)
\(=4x^2+4x+1=\left(2x+1\right)^2\)
\(j,x^3-x+y^3-y=x^3+y^3-x-y=\left(x+y\right)\left(x^2-xy+y^2\right)-\left(x+y\right)=\left(x+y\right)\left(x^2-xy+y^2-1\right)\)
(x + y)2 + x - y2
= x2 + 2xy + y2 + x - y2
= x2 + 2xy + (y2 - y2) + x
= x2 + 2xy + x
\(\left(x+y\right)^2+x-y^2\)
\(=x^2+2xy+y^2+x-y^2\)
\(=x^2+2xy+\left(y^2-y^2\right)+x\)
\(=x^2+2xy+x\)