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\(\frac{1}{7}+\frac{2}{9}+\frac{3}{10}+\frac{7}{9}+\frac{6}{7}+\frac{7}{10}\)
\(=\left(\frac{1}{7}+\frac{6}{7}\right)+\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{3}{10}+\frac{7}{10}\right)\)
\(=\frac{7}{7}+\frac{9}{9}+\frac{10}{10}=1+1+1=3\)
A)
\(\frac{7}{12}+\frac{3}{4}\times\frac{2}{4}\)
\(=\frac{7}{12}\times\left(\frac{3}{4}+\frac{2}{4}\right)\)
\(=\frac{35}{48}\)
B)
\(\frac{8}{9}-\frac{4}{15}:\frac{2}{5}\)
\(=\frac{8}{9}-\frac{2}{3}\)
\(=\frac{6}{27}\)
A. 3/6; 9/6; 1/3
B. 2/3; 8/6; 4/10
C. 10/15; 2/3; 8/12
D. 9/15; 2/3; 12/10
\(a,\dfrac{7}{6}+\dfrac{2}{5}=\dfrac{35}{30}+\dfrac{12}{30}=\dfrac{47}{30}\\ b,\dfrac{8}{12}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{17}{12}\\ c,4+\dfrac{9}{10}=\dfrac{40}{10}+\dfrac{9}{10}=\dfrac{49}{10}\\ d,\dfrac{2}{6}+3=\dfrac{1}{3}+3=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{10}{3}\)
\(\dfrac{7}{6}+\dfrac{2}{5}=\dfrac{35}{30}+\dfrac{12}{30}=\dfrac{35+12}{30}=\dfrac{47}{30}\)
\(\dfrac{8}{12}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{8+9}{12}=\dfrac{15}{12}=\dfrac{5}{4}\)
\(4+\dfrac{9}{10}=\dfrac{40}{10}+\dfrac{9}{10}=\dfrac{40+9}{10}=\dfrac{49}{10}\)
\(\dfrac{2}{6}+3=\dfrac{1}{3}+\dfrac{3}{1}=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{1+9}{3}=\dfrac{10}{3}\)
a: =5/4-3/4=2/4=1/2
b: =30/45-18/45=12/45=4/15
c: =10/12-9/12=1/12
d: =4/3-1/4=16/12-3/12=13/12
a) \(\frac{9}{22}\cdot\frac{33}{8}=\frac{3^2\cdot3\cdot11}{2\cdot11\cdot2^3}=\frac{3^4}{2^4}=\frac{81}{16}\)
b) \(\frac{12}{35}:\frac{36}{35}=\frac{2^2\cdot3}{2^2\cdot3^2}=\frac{1}{3}\)
c) \(\frac{19}{17}:\frac{76}{51}=\frac{19\cdot3\cdot17}{17\cdot2^2\cdot19}=\frac{3}{4}\)
a: \(\dfrac{15}{8}-\dfrac{13}{8}=\dfrac{15-13}{8}=\dfrac{2}{8}=\dfrac{1}{4}\)
b: \(\dfrac{7}{15}-\dfrac{2}{15}=\dfrac{7-2}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)
c: \(\dfrac{11}{12}-\dfrac{2}{12}=\dfrac{11-2}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
d: \(\dfrac{19}{7}-\dfrac{5}{7}=\dfrac{19-5}{7}=\dfrac{14}{7}=2\)
Đáp án B