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\(2S=2+2^2+...+2^{10}\)
\(2S-S=\left(2+2^2+...+2^{10}\right)-\left(1+2+...+2^9\right)\)
\(S=2^{10}-1=1023\)
\(5\cdot2^8=1280\)
\(\Rightarrow S< 5\cdot2^8\)
Ta có : S = 1 + 2 + 22 + 23 + ... + 29
2S = 2.(1 + 2 + 22 + 23 + ... + 29)
2S = 2 + 22 + 23 + ... + 29 + 210
2S - S = (2 + 22 + 23 + ... + 29 + 210) - (1 + 2 + 22 + 23 + ... + 29)
S = 210 - 1
Mà 210 - 1 = 28 . 4 - 1
Ta thấy 28 . 4 - 1 < 5.28 => S < 5.28
S > 5 . 28
vì 27 + 28 > 5x28
=> 1+2+22+......+29 > 5x28
=>đcpm
S=1+2+22+23+......+29
=>2S=2+22+23+...+210
=>2S-S=(2+22+23+...+210)-(1+2+22+23+......+29)
=>S=2+22+23+...+210-1-2-22-23-...-29
S=210-1
ta có : (4+1).28=4.28+28=22.28+28=210+28
=>210-1<210+28 hay
S<5.28
S = 1 + 2 + 2^2 + 2^3 + ... + 2^8
2S = 2(1 + 2 + 2^2 + 2^3 + ... + 2^8)
= 2 + 2^2 + 2^3 + 2^4 + ... + 2^9
2S - S = (2 + 2^2 + 2^3 + 2^4 + ... + 2^9) - (1 + 2 + 2^2 + 2^3 + ... + 2^8)
= 2^9 - 1
=> S = 2^9 - 1
Ta có: 5 . 2^8 = (4 + 1) . 2^8 = 4 . 2^8 + 2^8 = 2^2 . 2^8 + 2^8 = 2^10 + 2^8
Vì 2^9 - 1 < 2^10 + 2^8 => S < 5 . 2^8
tk cho mk nhé các bạn
thank you very much
chúc các bạn học giỏi
1/2T=2/22 +3/23 +4/24 +...+2017/22017
T-1/2T= (2/21+3/22+4/23+...+2017/22016)-(2/22+3/23+4/24+...+2017/22017)
1/2T=2/21+3/22+4/23+...+2017/22016-2/22-3/23-4/24-...-2017/22017
1/2T=1+(3/22-2/22)+(4/23-3/23)+...+(2017/22016-2016/22016)-2017/22017
1/2T=1+(1/22+1/23+1/24+...+1/22016)-2017/22017
xét A = 1/22+1/23+1/24+...+1/22016
phần này dễ bạn tự làm nhé
A=1/2-1/22016<1/2(vì 1/22016>0)
1/2T<1/21+1/2-(1/22016+2017/22017)
1/2T<3/2(vì 1/22016+2017/22017>0)
T<3/2:1/2
T<3
vậy T<3
1/2T=2/22 +3/23 +4/24 +...+2017/22017 T-1/2T= (2/21+3/22+4/23+...+2017/22016 )-(2/22+3/23+4/24+...+2017/22017 ) 1/2T=2/21+3/22+4/23+...+2017/22016 -2/22 -3/23-4/24 -...-2017/22017 1/2T=1+(3/22 -2/22 )+(4/23 -3/23 )+...+(2017/22016 -2016/22016 )-2017/22017 1/2T=1+(1/22+1/23+1/24+...+1/22016 )-2017/22017 xét A = 1/22+1/23+1/24+...+1/22016 phần này dễ bạn tự làm nhé A=1/2-1/22016<1/2(vì 1/22016>0) 1/2T<1/21+1/2-(1/22016+2017/22017 ) 1/2T<3/2(vì 1/22016+2017/22017>0) T<3/2:1/2 T<3
\(2A=2+2^2+...+2^{10}\)
\(2A-A=\left(2+2^2+...+2^{10}\right)-\left(1+2+...+2^9\right)\)
\(A=2^{10}-1=1023\)
mà \(5\cdot2^8=1280\Rightarrow A< 5\cdot2^8\)
A = 1 + 2+22+23+...+29
2A = 2 + \(2^2+2^3+2^4+...+2^{10}\)
\(-\)
\(A=1+2+2^2+2^3+...+2^9\)
\(A=\)\(1-2^{10}\)
KL= tự so sánh nha