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\(A=\dfrac{4^{10}+8^4}{4^5+8^6}\)
\(A=\dfrac{2^{20}+2^{12}}{2^{10}+2^{18}}=\dfrac{\left(2^8+1\right).2^{12}}{\left(1+2^8\right).2^{10}}\)
\(=\dfrac{\left(256+1\right).2^2}{1+256}=\dfrac{257.2^2}{257}=2^2\)
\(B=\dfrac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
\(=\dfrac{1+81+6561+3^{12}}{1+9+81+729+6561+59049+3^{12}+3^{14}}\)
\(=\dfrac{6643+3^{12}}{91+719+6561+59049+3^{12}+3^{14}}\)
\(=\dfrac{6643+3^{12}}{66430+3^{12}+3^{14}}\)
P/s : Nổi hứng lên thì lm chứ k bt đúng hay sai :V
Ta có
• A=1+34+38+312
=>34.A=34+38+312+316
<=>81.A-A=316-1
<=>A=(316-1)/80=538084
•B=1+32+34+36+38+310+312+314
=>32.B=32+34+36+38+310+312+314+316
<=>8.B=316-1
<=>B=(316-1)/8=53808400
Vậy Q=A/B=538084/53808400=1/100=0.01
\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+\left(3^2+3^6+3^{10}+3^{14}\right)}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+3^2\left(1+3^4+3^8+3^{12}\right)}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)\left(1+3^2\right)}\)
\(=\frac{1}{1+3^2}\)\(=\frac{1}{10}\)
\(\frac{4^{10}+8^4}{4^5+8^6}=\frac{\left(2^2\right)^{10}+\left(2^3\right)^4}{\left(2^2\right)^5+\left(2^3\right)^6}=\frac{2^{2.10}+2^{3.4}}{2^{2.5}+2^{3.6}}=\)
\(=\frac{2^{20}+2^{12}}{2^{10}+2^{18}}\)
Lời giải:
\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}=\frac{1+3^4+3^8+3^{12}}{(1+3^4+3^8+3^{12})+(3^2+3^6+3^{10}+3^{14})}\)
\(=\frac{1+3^4+3^8+3^{12}}{(1+3^4+3^8+3^{12})+3^2(1+3^4+3^{8}+3^{12})}\)
\(=\frac{1+3^4+3^8+3^{12}}{(1+3^2)(1+3^4+3^8+3^{12})}=\frac{1}{1+3^2}=\frac{1}{10}\)
Lời giải:
\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}=\frac{1+3^4+3^8+3^{12}}{(1+3^4+3^8+3^{12})+(3^2+3^6+3^{10}+3^{14})}\)
\(=\frac{1+3^4+3^8+3^{12}}{(1+3^4+3^8+3^{12})+3^2(1+3^4+3^{8}+3^{12})}\)
\(=\frac{1+3^4+3^8+3^{12}}{(1+3^2)(1+3^4+3^8+3^{12})}=\frac{1}{1+3^2}=\frac{1}{10}\)