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2 tháng 7 2016
\(M=\frac{2.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}{-5.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}+\frac{\frac{1}{17}-\frac{1}{23}+\frac{1}{31}}{3.\left(\frac{1}{17}-\frac{1}{23}+\frac{1}{31}\right)}=-\frac{2}{5}+\frac{1}{3}=\frac{1}{15}.\)
C
8 tháng 3 2023
`a)1 4/23 + ( 5/21-4/23)+16/21-1/2`
`=27/23+5/21-4/23+16/21-1/2`
`=(27/23-4/23)+(5/21+16/21)-1/2`
`=23/23+21/21-1/2`
`=1+1-1/2`
`=2-1/2`
`=4/2-1/2`
`=3/2`
___
`b)75%-(5/2+5/3)+(-1/2)^3`
`=3/4-5/2+5/3+(-1/8)`
`=(3/4-5/2-1/8)+5/3`
`=(6/8-20/8-1/8)+5/3`
`=-15/8+5/3`
`=-45/24+40/24`
`=-5/24`
___
`c)-3/4(-55/9).8/11`
`=-3/4.(-40/9)`
`=-10/3`
__
`d)-3/8 . 6/13 + 7/13 . (-3/8) + 1 3/8`
`= -3/8 . (6/13 + 7/13) + 11/8`
`= -3/8 . 13/13 + 11/8`
`= -3/8 .1 + 11/8`
`= -3/8 + 11/8`
`= 8/8`
`=1`
5 tháng 4 2021
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
5 tháng 4 2021
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
TT
1
21 tháng 9 2020
a) (x + 23) - 14 = 11
=> x + 23 - 14 = 11
=> x + 9 = 11
=> x = 11 - 9 = 2
b) 2.x + 13 = 43
=> 2.x = 43 - 13
=> 2.x = 30
=> x = 15
c) 2(x - 1) - 156 = 196
=> 2x - 2 = 352
=> 2x = 354
=> x = 177
3(134 - x) + 1 = 211
=> 3(134 - x) = 210
=> 134 - x = 70
=> x = 134 - 70 = 64
h) 156 - 2(x + 2) = 128
=> 2(x + 2) = 156 - 128 = 28
=> x + 2 = 28 : 2
=> x + 2 = 14
=> x = 12
8 tháng 12 2021
\(\left\{2^3+\left[1+\left(3-1\right)^2\right]\right\}:13\)
\(=\left(8+1+2^2\right):13\)
\(=13:13\)
\(=1\)
Giúp e với :0
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]}: 13
= [8 + (1 +
)] : 13
= [8 + (1 + 4)] : 13
= (8 + 5) : 13= 13 : 13 = 1