Câu hỏi của Nguyễn Thị Gia Linh

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『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』 · Accepted Answer

`@` `\text {Ans}``\downarrow``1,``a)`$\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{7+12}{19}=\dfrac{19}{19}=1$`b)`$\dfrac{5}{13}+\dfrac{4}{13}=\dfrac{5+4}{13}=\dfrac{9}{13}$`c)`$\dfrac{24}{11}-\dfrac{13}{11}=\dfrac{24-13}{11}=\dfrac{11}{11}=1$`d)`$\dfrac{35}{8}-\dfrac{19}{8}=\dfrac{35-19}{8}=\dfrac{16}{8}=2$Câu trả lời: `@` `\text {Ans}``\downarrow``1,``a)`$\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{7+12}{19}=\dfrac{19}{19}=1$`b)`$\dfrac{5}{13}+\dfrac{4}{13}=\dfrac{5+4}{13}=\dfrac{9}{13}$`c)`$\dfrac{24}{11}-\dfrac{13}{11}=\dfrac{24-13}{11}=\dfrac{11}{11}=1$`d)`$\dfrac{35}{8}-\dfrac{19}{8}=\dfrac{35-19}{8}=\dfrac{16}{8}=2$

『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』 · Answer

`2,``a)`$\dfrac{3}{7}+\dfrac{5}{4}=\dfrac{12}{28}+\dfrac{35}{28}=\dfrac{12+35}{28}=\dfrac{47}{28}$`b)`$\dfrac{4}{5}+\dfrac{12}{10}=\dfrac{8}{10}+\dfrac{12}{10}=\dfrac{8+12}{10}=\dfrac{20}{10}=2$`c)`$\dfrac{12}{8}-\dfrac{4}{9}=\dfrac{108}{72}-\dfrac{32}{72}=\dfrac{76}{72}=\dfrac{19}{18}$`d)`$\dfrac{2}{7}-\dfrac{3}{14}=\dfrac{4}{14}-\dfrac{3}{14}=\dfrac{1}{14}$Câu trả lời: `2,``a)`$\dfrac{3}{7}+\dfrac{5}{4}=\dfrac{12}{28}+\dfrac{35}{28}=\dfrac{12+35}{28}=\dfrac{47}{28}$`b)`$\dfrac{4}{5}+\dfrac{12}{10}=\dfrac{8}{10}+\dfrac{12}{10}=\dfrac{8+12}{10}=\dfrac{20}{10}=2$`c)`$\dfrac{12}{8}-\dfrac{4}{9}=\dfrac{108}{72}-\dfrac{32}{72}=\dfrac{76}{72}=\dfrac{19}{18}$`d)`$\dfrac{2}{7}-\dfrac{3}{14}=\dfrac{4}{14}-\dfrac{3}{14}=\dfrac{1}{14}$

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