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\(a,\left(a-b+c\right)-\left(a+c\right)=a-b+c-a-c=-b\)
\(b,\left(a+b\right)-\left(b-a\right)+c=a+b-b+a+c=2a+c\)
\(c,-\left(a+b-c\right)+\left(a-b-c\right)=-a-b+c+a-b-c=-2b\)
\(d,a\left(b+c\right)-a\left(b+d\right)=ab+ac-ab-ad=ac-ad=a\left(c-d\right)\)
\(e,a\left(b-c\right)+a\left(d+c\right)=ab-ac+ad+ac=ab+ad=a\left(b+d\right)\)
a) (a - b + c) - (a + c)
= a - b + c - a - c
= (a - a) - b + (c - c)
= -b
b) (a + b) - (b - a) + c
= a + b - b + a + c
= 2a + (b - b) + c
= 2a + c
c) - (a + b - c) + (a - b - c)
= -a - b + c + a - b - c
= (-a + a) - (b + b) + (c - c)
= -2b
d) a(b + c) - a(b + d)
= ab + ac - ab - ad
= (ab - ab) + (ac - ad)
= ac - ad
= a(c - d)
e) a(b - c) + a(d + c)
= a(b - c + d + c)
= a[b - (c - c) + d]
= d(b + d)
a, (a-b+c)-(a+c)=-b
<=>a-b+c-a-c=-b
<=>(a-a)+(c-c)-b=-b
<=>0+0-b=-b
<=>-b=-b
Vậy (a-b+c)-(a+c)=-b
b) (a+b)-(b-a)+c=2a+c
<=>a+(b-b)+a+c=2a+c
<=>a+a+c=2a+c
<=>2a+c=2a+c
Vậy (a+b)-(b-a)+c=2a+c
c) -(a+b-c)+(a-b-c)=-2b
<=>-a-b+c+a-b-c=-2b
<=>(-a+a)+(c-c)-(b+b)=-2b
<=>0+0-2b=-2b
<=>-2b=-2b
Vậy -(a+b-c)+(a-b-c)=-2b
d) a(b+c)-a(b+d)=a(c-d)
<=>ab+ac-ab-ad=a(c-d)
<=>a(b+c-b-d)=a(c-d)
<=>a(c-d)=a(c-d)
Vậy a(b+c)-a(b+d)=a(c-d)
e) a(b-c)+a(c+d)=a(b+d)
<=>ab-ac+ac+ad=a(b+d)
<=>a(b-c+c+d)=a(b+d)
<=>a(b+d)=a(b+d)
Vậy a(b-c)+a(c+d)=a(b+d)
1) (a-b+c)-(a+c)=-b=a-b+c-a-c=-b
2)(a+b)-(b-a)=2a+c=a+b-b+c+c=2c+a(ko the bang 2a+c)
3)-(a+b-c)+(a-b-c)=-a-b+c+c-b-c=-2c
tk minh nha
lam dc the thoi
a)(a-b+c)-(a+c)
=a-b+c-a-c
=a-a - b + c-c
=-b
b)(a+b)-(b-a)+c
=a+b-b+a+c
=a+a+c
=2a+c
c)-(a+b-c) +(a-b-c)
= -a -b+c+a-b-c
=-a+a-b-b+c-c
=-2b
d) a(b+c) - a(b+d)
= ab + ac - ab - ad
= ab-ab+ac-ad
=a(c-d)
e) a(b-c) + a(d+c)
= ab -ac + ad + ac
= ab +ad -ac + ac
=a(b+d)
a)(a-b+c)-(a+c)
=a-b+c-a-c=a-a+c-c-b
=0-b=-b
b)(a+b)-(b-a)+c
=a-b-b+a+c=2a+c
a, (a-b+c)-(a+c)=-b
<=>a-b+c-a-c=-b
<=>(a-a)+(c-c)-b=-b
<=>0+0-b=-b
<=>-b=-b
Vậy (a-b+c)-(a+c)=-b
b) (a+b)-(b-a)+c=2a+c
<=>a+(b-b)+a+c=2a+c
<=>a+a+c=2a+c
<=>2a+c=2a+c
Vậy (a+b)-(b-a)+c=2a+c
c) -(a+b-c)+(a-b-c)=-2b
<=>-a-b+c+a-b-c=-2b
<=>(-a+a)+(c-c)-(b+b)=-2b
<=>0+0-2b=-2b
<=>-2b=-2b
Vậy -(a+b-c)+(a-b-c)=-2b
d) a(b+c)-a(b+d)=a(c-d)
<=>ab+ac-ab-ad=a(c-d)
<=>a(b+c-b-d)=a(c-d)
<=>a(c-d)=a(c-d)
Vậy a(b+c)-a(b+d)=a(c-d)
e) a(b-c)+a(c+d)=a(b+d)
<=>ab-ac+ac+ad=a(b+d)
<=>a(b-c+c+d)=a(b+d)
<=>a(b+d)=a(b+d)
Vậy a(b-c)+a(c+d)=a(b+d)
a) (a-b+c)-(a+c)
= a-b+c-a-c
=-b
b) (a+b)-(b-a)+c
=a+b-b+a+c
=2a+c
c) -(a+b-c)+(a-b-c)
=-a-b+c+a-b-c
=-2b
d) a(b+c)-a(b+d)
=ab+ac-ab-ad
=ac-ad
=a(c-d)
e) a(b-c)+a(d+c)
= ab-ac+ad+ac
=ab+ad
=a(b+d)