Question

[Hoàng Đình Nam]

Giúp mình với 

Answer 1

[Toru]

a) $x(2x-3)-2x^2=10$

$\Rightarrow 2x^2-3x-2x^2=10$

$\Rightarrow -3x=10$

$\Rightarrow x=\frac{-10}{3}$

Vậy $x=\frac{-10}{3}$.

---------------------------------------

b) $(x-2)(2x+5)-(2x-1)x=2$

$\Rightarrow x(2x+5)-2(2x+5)-2x^2+x=2$

$\Rightarrow 2x^2+5x-4x-10-2x^2+x=2$

$\Rightarrow 2x-10=2$

$\Rightarrow 2x=2+10$

$\Rightarrow 2x=12$

$\Rightarrow x=12:2$

$\Rightarrow x=6$

Vậy $x=6$.

$\text{#}Toru$