Question

[M r . V ô D a n h]

giải ch tiết ra hết nha

Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 2: 

b) Ta có: |x-1.5|=2

nên \(\left[{}\begin{matrix}x-\dfrac{3}{2}=2\\x-\dfrac{3}{2}=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=\dfrac{-1}{2}\end{matrix}\right.\)

c) Ta có: \(\dfrac{4}{5}-\left|x-\dfrac{1}{6}\right|=\dfrac{2}{3}\)

nên \(\left|x-\dfrac{1}{6}\right|=\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{6}=\dfrac{2}{15}\\x-\dfrac{1}{6}=-\dfrac{2}{15}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{10}\\x=\dfrac{1}{30}\end{matrix}\right.\)

d) Ta có: \(3^x\cdot2^x=216\)

nên \(6^x=216\)

hay x=3