Question

[ha cam]

giải bất pt: 

\(\frac{1}{2}\)log₂x - log₅x > 1

Answer 1

[Richard Lộc]

ĐK;x>0
<=> \(\frac{1}{2}\)log₂x-log₂x-log₅2>1

<=>\(\frac{1}{2}\)log₂x>1+log₅2

<=> log₂x>\(\frac{1+log_{ }^{ }}{2}\)( ví a=2>0)

<=>x>2^{\(\frac{1+log_{ }^{ }}{2}\)}