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9/5:17/15+8/5:17/15
c1:=17/15:(9/5+8/5)
=17/15:17/5=1
c2=27/17+24/17
=51/17
\(2\frac{4}{3}+\frac{4}{12}=\frac{2.3+4}{3}+\frac{4}{12}=\frac{10}{3}+\frac{4}{12}=\frac{40}{12}+\frac{4}{12}=\frac{44}{12}=\frac{11}{3}\)
\(2\frac{4}{3}=\frac{10}{3}\)
\(\frac{10}{3}+\frac{4}{12}=\frac{120}{36}+\frac{12}{36}\)
\(=\frac{132}{36}=\frac{22}{6}=\frac{11}{3}\)
2\(\frac{2}{12}\)+ X = \(\frac{5}{7}\)+ \(\frac{8}{12}\)
\(\frac{13}{6}\)+ X=\(\frac{29}{21}\)
X= \(\frac{29}{21}\)- \(\frac{13}{6}\)
X=\(\frac{-11}{14}\)
\(|2^2_{12}\)\(+x=\frac{5}{7}+\frac{8}{12}\)
\(2+x=\frac{5}{7}+\frac{1}{2}\)
\(2+x=\frac{17}{14}\)
\(x=\frac{17}{14}-2\)
\(x=\frac{-11}{14}\)
Ta có: \(\frac{54}{195}-\frac{1}{2}=\frac{108}{390}-\frac{195}{390}\)
\(=-\frac{87}{390}=-\frac{29}{130}\)
Vậy \(\frac{54}{195}-\frac{1}{2}=-\frac{29}{130}\)
\(đổi9\frac{3}{2}=\frac{21}{2}\)
\(\frac{9}{2}+\frac{21}{2}=\frac{30}{2}=15\)
\(=15\)
= 9/2 + 21/2
=15