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27 tháng 5 2017

9/5:17/15+8/5:17/15

c1:=17/15:(9/5+8/5)

    =17/15:17/5=1

c2=27/17+24/17

    =51/17

27 tháng 5 2017

C1 : \(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)

\(=\frac{27}{17}+\frac{24}{17}\)

\(=3\)

C2 : \(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)

\(=\left(\frac{9}{5}+\frac{8}{5}\right):\frac{17}{15}\)

\(=\frac{17}{5}:\frac{17}{15}\)

\(=3\)

23 tháng 4 2017

\(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)

\(=\frac{9}{5}\times\frac{15}{17}+\frac{8}{5}\times\frac{15}{17}\)

\(=\frac{15}{17}\times\left(\frac{9}{5}+\frac{8}{5}\right)\)

\(=\frac{15}{17}\times\frac{17}{5}\)

\(=3\)

h minh nhen

20 tháng 4 2019

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10 tháng 5 2017

\(\frac{24}{75}\)\(\frac{8}{15}\)\(\frac{10}{9}\) = \(\frac{24}{75}\) X \(\frac{15}{8}\)\(\frac{10}{9}\)\(\frac{8x3x5x3x5x2}{15x5x8x3x3}\)\(\frac{2}{3}\)

mình trả lời nhanh nhất nha, nhớ tk cho mình đấy

10 tháng 5 2017

2/3 nha bn, bn k đi r mk kb cho

13 tháng 9 2017

a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)

\(=2\)

b) \(\frac{5}{9}\times\frac{1}{2}\times\frac{5}{9}\times\frac{6}{4}=\frac{25}{81}\times\frac{3}{4}=\frac{25}{108}\)

c) \(\frac{7}{8}\div\frac{1}{2}+\frac{9}{8}\div\frac{1}{2}=\left(\frac{7}{8}+\frac{9}{8}\right)\div\frac{1}{2}\)

\(=2\div\frac{1}{2}=4\)

d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)

\(=1+\frac{1}{2}=\frac{3}{2}\)

13 tháng 9 2017

a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)

\(=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)

\(=1+1\)

\(=2\)

b) \(\frac{5}{9}.\frac{1}{2}.\frac{5}{9}.\frac{6}{4}\)

\(=\left(\frac{5}{9}\right)^2\left(\frac{1}{2}.\frac{6}{4}\right)\)

\(=\frac{25}{81}.\frac{3}{4}\)

\(=\frac{25}{108}\)

c) \(\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)

\(=\frac{7}{8}.2+\frac{9}{8}.2\)

\(=2\left(\frac{7}{8}+\frac{9}{8}\right)\)

\(=2.\frac{16}{8}\)

\(=2.2\)

\(=4\)

d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)

\(=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)

\(=1+\frac{1}{2}\)

\(=\frac{2}{2}+\frac{1}{2}\)

\(=\frac{3}{2}\)

13 tháng 9 2017

a,(11/15+4/15)+(5/7+2/7)

=1+1

=2

b,5/9x(1/2+6/4)

=5/9x2

=10/9

c,1/2:(7/8+9/8)

=1/2:2

=1

d,(17/10-7/10)+1/2

=1+1/2

=3/2

13 tháng 9 2017

a ) (11/15+4/15 ) + ( 5/7 +2 /7 )

=1+1

= 2

b)5/9 x ( 1/ 2 + 6/ 4 )

= 5/9 x 2

=10/9 

c) 17/10-5/10-7/10

=(17-5-7) / 10

= 5/10

2 tháng 10 2019
=(4/17+13/17)+(-7/15-8/15)+(5/8-7/16) =1+(-1)+3/16 =3/16
2 tháng 10 2019

ko sai đâu nha bạn

3 tháng 4 2015

C1:(9/5+8/5):17/15=17/5:17/15=3(nhớ bình chọn nha)

C2;27/17+24/17=3(nhớ bình chọn nha)

3 tháng 4 2015

cách 1: \(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}=\frac{9}{5}.\frac{15}{17}+\frac{8}{5}.\frac{15}{17}=\frac{15}{17}.\left(\frac{9}{5}+\frac{8}{5}\right)=\frac{15}{17}.\frac{17}{5}=3\)

cách 2: \(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}=\frac{9}{5}.\frac{15}{17}+\frac{8}{5}.\frac{15}{17}=3.\frac{3}{17}+8.\frac{3}{17}=\frac{27}{17}+\frac{24}{17}=\frac{51}{17}=3\)

\(A=\dfrac{1}{5\times7}+\dfrac{1}{7\times9}+\dfrac{1}{9\times11}+...+\dfrac{1}{87\times89}\)

\(A=\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+...+\dfrac{1}{87}-\dfrac{1}{89}\)

\(A=\dfrac{1}{5}-\left(\dfrac{1}{7}-\dfrac{1}{7}\right)-\left(\dfrac{1}{9}-\dfrac{1}{9}\right)-...-\left(\dfrac{1}{87}-\dfrac{1}{87}\right)-\dfrac{1}{89}\)

\(A=\dfrac{1}{5}-\dfrac{1}{89}\)

\(A=\dfrac{84}{445}\)

Vậy, `A=84/445.`

6 tháng 6 2023

A = \(\dfrac{1}{5\times7}\) + \(\dfrac{1}{7\times9}\)+\(\dfrac{1}{9\times11}\)+...+\(\dfrac{1}{87\times89}\)

A = \(\dfrac{1}{2}\) \(\times\)(  \(\dfrac{2}{5\times7}\)+\(\dfrac{2}{7\times9}\)+\(\dfrac{2}{9\times11}\)+...+\(\dfrac{2}{87\times89}\))

A = \(\dfrac{1}{2}\) \(\times\) ( \(\dfrac{1}{5}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{11}\) +...+ \(\dfrac{1}{87}\) - \(\dfrac{1}{89}\))

A = \(\dfrac{1}{2}\) \(\times\) (\(\dfrac{1}{5}\) - \(\dfrac{1}{89}\))

A = \(\dfrac{1}{2}\) \(\times\) \(\dfrac{84}{445}\) 

A = \(\dfrac{42}{445}\)