\(\frac{4^9.9^4-10.6^9}{2^{10}.3^8+6^8-28}\)

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14 tháng 5 2019

\(\frac{4^9.9^4-10.6^9}{2^{10}.3^8+6^8-28}=\frac{2^{18}.3^8-2.5.2^9.3^9}{2^{10}.3^8+2^8.6^8-2^2.7}\)

Nhóm các tích trên tử và mẫu sao cho bằng nhau rồi tính.

14 tháng 5 2019

\(=\frac{\left(2^2\right)^9.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8-28}\)

\(=\frac{2^{18}.3^8-2.5.2^9.3^9}{2^{10}3^8+2^8.3^8-28}\)

\(=\frac{2^{18}.3^8-2^{10}.3^9.5}{2^8.3^8.\left(2^2+1\right)-28}\)

\(=\frac{2^{10}.3^8.\left(2^8-3.5\right)}{2^8.3^8.5-28}\)

\(=\frac{2^2.\left(2^8-3.5\right)}{5-28}\)

\(=\frac{2.\left(256-15\right)}{-23}\)

\(=\frac{-482}{23}\)

12 tháng 1 2020

lamf như thế nào

25 tháng 10 2017

\(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(B=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+3^{10}.2^{20}}\)

\(B=\frac{2^{19}.3^9+3^9.5.2^{18}}{2^{19}.3^9+3^{10}.2^{20}}\)

\(B=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9\left(1+3.2\right)}\)

\(B=\frac{7}{2.7}\)

\(B=\frac{1}{2}\)

\(C=\frac{2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)

\(C=\frac{2^{13}.2^{22}-2^{36}}{3^2.2^{34}}\)

\(C=\frac{2^{35}-2^{36}}{3^2.2^{34}}\)

\(C=\frac{2^{35}\left(1-2\right)}{3^2.2^{34}}\)

\(C=\frac{-2}{9}\)

\(D=\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)

\(D=\frac{2^{14}.2^8}{3.2^{15}.2^8-5.2^2.2^{20}}\)

\(D=\frac{2^{14}.2^8}{3.2^{23}-5.2^{22}}\)

\(D=\frac{2^{22}}{2^{22}\left(3.2-5\right)}\)

\(D=1\)

16 tháng 9 2016

\(H=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(H=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)

\(H=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(H=\frac{2^{19}.3^9+2^{18}.5.3^9}{2^{19}.3^9+2^{20}.3^{10}}\)

\(H=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9.\left(1+2.3\right)}\)

\(H=\frac{2^{18}.3^9.7}{2^{19}.3^9.\left(1+6\right)}\)

\(H=\frac{2^{18}.3^9.7}{2^{19}.3^9.7}=\frac{1}{2}\)

\(K=\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)

\(K=\frac{\left(2^2\right)^7.2^8}{3.2^{15}.\left(2^4\right)^2-5.2^2.2^{20}}\)

\(K=\frac{2^{14}.2^8}{3.2^{15}.2^8-5.2^{22}}\)

\(K=\frac{2^{22}}{3.2^{23}-5.2^{22}}\)

\(K=\frac{2^{22}}{2^{22}.\left(3.2-5\right)}=\frac{2^{22}}{2^{22}.1}=1\)

12 tháng 6 2017

\(1,\)

\(\dfrac{45^2.3^8.10^5}{5^5.3^7.18^5}\)

\(=\dfrac{3^4.5^2.3^8.2^5.5^5}{5^5.3^7.2^5.3^{10}}\)

\(=\dfrac{3^{12}.2^5.5^7}{5^5.3^{17}.2^5}\)

\(=\dfrac{1.5^2}{3^5.1}\)

\(=\dfrac{25}{243}\)

\(2,\)

\(\dfrac{4^5.9^4+2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\dfrac{2^{10}.3^8+2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8+2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\dfrac{2^{10}.3^8.4}{2^{10}.3^8.6}\)

\(=\dfrac{2^{12}.3^8}{2^{11}.3^9}\)

\(=\dfrac{2}{3}\)

\(3,\)

\(\dfrac{15.3^{11}+4.27^4}{9^7}\)

\(=\dfrac{3.5.3^{11}+2^2.3^{12}}{3^{14}}\)

\(=\dfrac{5.3^{12}+2^2.3^{12}}{3^{14}}\)

\(=\dfrac{3^{12}\left(5+2^2\right)}{3^{14}}\)

\(=\dfrac{3^{12}.9}{3^{14}}\)

\(=\dfrac{3^{14}}{3^{14}}\)

\(=1\)

\(4,\)

\(\dfrac{4^7.2^8}{3.2^{15}.16^2-5^2\left(2^{10}\right)^2}\)

\(=\dfrac{2^{22}}{3.2^{23}-5^2.2^{20}}\)

\(=\dfrac{2^{22}}{2^{20}.\left(-1\right)}\)

\(=\dfrac{2^{22}}{-2^{20}}\)

\(=-4\)

* Mấy bài còn lại tương tự đấy bạn tự làm đi

Mình mỏi tay lắm rồi

12 tháng 6 2017

P/s:khuyến khích tự làm,chỉ làm mẫu 1 câu:

1)\(\dfrac{45^2.3^8.10^5}{5^5.3^7.18^5}=\dfrac{\left(5.9\right)^2.3.3^7.\left(2.5\right)^5}{5^5.3^7.\left(2.9\right)^5}\)\(=\dfrac{5^2.9^2.3.3^7.2^5.5^5}{5^5.3^7.2^5.9^5}\)\(=\dfrac{5^2.9^2.3.1.1.1}{1.1.1.9^5}\)\(=\dfrac{5^2.9^2.3}{9^5}=\dfrac{5^2.9^2.3}{9^2.9^3}=\dfrac{5^2.3}{9^3}=\dfrac{75}{729}=\dfrac{25}{243}\)

8 tháng 4 2017

1/2+2/3+3/4+4/5+5/6+6/7+7/8+8/9+9/10x9/10

=9/10x(1/2+2/3)+(3/4+4/5)+(5/6+6/7)+(7/8+8/9)

=9/10x(1/3+3/5+5/7+7/9)

9/10x(1/3+3/5)+(5/7+7/9)

=9/10x1/5+5/9

9/50+5/9

=10

8 tháng 10 2017

Bn Long làm đúng rồi bn avt154519_60by60.jpg  nguyễn kim arica cứ làm theo cách đó là được .

Bn nào thấy đúng thì ủng hộ nha .

8 tháng 6 2017

\(\frac{60}{100}+\frac{8}{50}+\frac{9}{20}=\frac{60}{100}+\frac{16}{100}+\frac{45}{100}=\frac{60+16+45}{100}=\frac{121}{100}\)

\(\frac{3}{4}-\frac{6}{7}\)\(+\frac{9}{28}=\frac{21}{28}-\frac{24}{28}+\frac{9}{28}=\frac{21-24+9}{28}=\frac{6}{28}=\frac{3}{14}\)

8 tháng 6 2017

a)\(\frac{60}{100}+\frac{8}{50}+\frac{9}{20}=\frac{60}{100}+\frac{16}{100}+\frac{45}{100}=\frac{60+16+45}{100}=\)\(\frac{121}{100}\)

b) \(\frac{3}{4}-\frac{6}{7}+\frac{9}{28}=\frac{21}{28}-\frac{24}{28}+\frac{9}{28}=\frac{21}{28}+\frac{9}{28}-\frac{24}{28}\)\(=\)\(\frac{29}{28}-\frac{24}{28}=\frac{29-24}{28}=\frac{5}{28}\)

25 tháng 3 2017

mk giải cho câu A rồi tự suy mấy câu khác nhé!

ta có : A = 10^8 + 2/10^8 - 1

     => A = 10^8 - 1 + 3/10^8 - 1

     => A = 1+ 3/10^8 - 1

          B = 10^8/10^8 - 3

    =>  B = 10^8 - 3 + 3/10^8 - 3

    =>  B = 1+ 3/10^8 - 3

vì 3/10^8 - 1 < 3/10^8 - 3

=> 1 + 3/10^8 - 1 < 1 + 3/10^8 - 3

=> A < B

vậy A < B

cách này cô dạy mk đó