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\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)-\left(\frac{-15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=\left(\frac{-1}{4}-\frac{5}{3}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{6}{11}\right)+\frac{48}{49}\)
\(=\left(\frac{-3}{12}-\frac{20}{12}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{18}{33}\right)+\frac{48}{49}\)
\(=\left(\frac{-23}{12}+\frac{15}{12}\right)+\left(\frac{-11}{33}\right)+\frac{48}{49}\)
\(=\frac{-2}{3}+\left(\frac{-1}{3}\right)+\frac{48}{49}\)
\(=-1+\frac{48}{49}\)
\(=-\frac{1}{49}\)
Ùng hộ mk nha ^_-
( -1,25) . 14,7. ( -8 )
= \(\frac{-5}{4}\). \(\frac{147}{10}\)\(.\frac{\left(-8\right)}{1}\)
= \(\frac{\left(-5\right).147.\left(-8\right)}{4.10.1}.\)
= \(\frac{\left[\left(-5\right).\left(-8\right)\right].147}{\left(4.10\right).1}\)
= \(\left[\frac{-5}{4}.\frac{-8}{10}\right].147\)
=147
\(=\left(-\frac{1}{4}-\frac{5}{3}\right)+\frac{7}{33}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=-\frac{23}{12}+\frac{7}{33}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=\left(-\frac{23}{12}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{6}{11}\right)+\frac{48}{49}\)
\(=-\frac{2}{3}-\frac{1}{3}+\frac{48}{49}\)
\(=-\frac{3}{3}+1-\frac{1}{49}\)
\(=-1+1-\frac{1}{49}\)
\(=-\frac{1}{49}\)
C1:
= \(-\frac{1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}=\left(-\frac{1}{4}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{5}{3}-\frac{6}{11}\right)+\frac{48}{49}\)
=\(1-2+\frac{48}{49}=\frac{48}{49}-1=-\frac{1}{49}\)
(-1/4+9/33-5/3)-(-5/4+6/11-48/49)
= -1/4+9/33-5/3+5/4-6/11+48/49
= -1/4+9/33+(-5/3)+5/4+(-6/11)+48/49
= 65/1617
a) \(\frac{-3}{5}.y=\frac{21}{10}\)
\(y=\frac{21}{10}:\frac{-3}{5}\)
\(y=\frac{-7}{2}\)
vậy \(y=\frac{-7}{2}\)
b) \(y:\frac{3}{8}=-1\frac{31}{33}\)
\(y:\frac{3}{8}=\frac{-64}{33}\)
\(y=\frac{-64}{33}.\frac{3}{8}\)
\(y=\frac{-8}{11}\)
vậy \(y=\frac{-8}{11}\)
c) \(1\frac{2}{5}.y+\frac{3}{7}=\frac{-4}{5}\)
\(\frac{7}{5}.y+\frac{3}{7}=\frac{-4}{5}\)
\(\frac{7}{5}.y=\frac{-4}{5}-\frac{3}{7}\)
\(\frac{7}{5}.y=\frac{-43}{35}\)
\(y=\frac{-43}{35}:\frac{7}{5}\)
\(y=\frac{-43}{49}\)
vậy \(y=\frac{-43}{49}\)
d) \(\frac{-11}{12}.y+0,25=\frac{5}{6}\)
\(\frac{-11}{12}.y=\frac{5}{6}-0,25\)
\(\frac{-11}{12}.y=\frac{7}{12}\)
\(y=\frac{7}{12}:\frac{-11}{12}\)
\(y=\frac{-7}{11}\)
vậy \(y=\frac{-7}{11}\)
\(\frac{33-33:\frac{11}{6}}{\frac{6}{11}}\)
\(=\frac{33-33\cdot\frac{6}{11}}{\frac{6}{11}}\)
\(=\frac{33-33\cdot1}{1}\)
\(=33-33=0\)
\(\frac{33-33:\frac{11}{6}}{\frac{6}{11}}\)
\(=\frac{33-33\cdot\frac{6}{11}}{\frac{6}{11}}\)
\(=\frac{33-18}{\frac{6}{11}}\)
\(=\frac{15}{\frac{6}{11}}\)
\(=\frac{55}{2}\)