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a: Đề thiếu vế phải rồi bạn
b: \(\Leftrightarrow x\cdot\dfrac{-12}{13}=6+\dfrac{1}{13}+5=11+\dfrac{1}{13}=\dfrac{144}{13}\)
hay x=-12
c: \(\Leftrightarrow x\cdot\dfrac{-5}{4}-\dfrac{6}{5}x=\dfrac{-1}{2}-\dfrac{3}{7}\)
\(\Leftrightarrow x\cdot\dfrac{-49}{20}=\dfrac{-13}{14}\)
hay x=130/343
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}-\frac{x+2}{14}-\frac{x+2}{15}=0\\ \Leftrightarrow\left(x+2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)=0\\ \Rightarrow x+2=0\Leftrightarrow x=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\frac{13-x}{x+15}=\frac{2}{3}\)
\(\Rightarrow3\left(13-x\right)=2\left(x+15\right)\)
\(\Rightarrow39-3x=2x+30\)
\(\Rightarrow5x=9\)
\(\Rightarrow x=\frac{9}{5}\)
\(\frac{13-x}{x+15}=\frac{2}{3}\Rightarrow3\left(13-x\right)=2\left(x+15\right)\)
\(\Rightarrow39-3x=2x+30\)
\(\Rightarrow5x=9\)
\(\Rightarrow x=\frac{9}{5}\)
\(\frac{13-x}{x+15}=\frac{2}{3}\)
\(\Rightarrow3\left(13-x\right)=2\left(x+15\right)\)
\(\Rightarrow36-3x=2x+30\)
\(\Rightarrow-3x-2x=-36+30\)
\(\Rightarrow-5x=-6\)
\(\Rightarrow x=\frac{6}{5}\)
\(\Rightarrow\left(13-x\right).3=\left(x+15\right).2\)
\(39-3x=2x+30\)
\(-3x-2x=-39+30\)
\(-5x=-9\)
\(x=\frac{9}{5}\)