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Chỗ cuối mk nhầm, sửa lại nha :
\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{90}+\frac{1}{100}\)
\(=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+...+\frac{1}{9\times10}+\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{9}-\frac{1}{10}+\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{10}+\frac{1}{100}\)
\(=\frac{50}{100}-\frac{10}{100}+\frac{1}{100}\)
\(=\frac{41}{100}\)
\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{90}+\frac{1}{100}\)
\(=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+...+\frac{1}{9\times10}+\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{9}-\frac{1}{10}+\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{10}+\frac{1}{100}\)
\(=\frac{50}{100}-\frac{10}{100}-\frac{1}{100}\)
\(=\frac{39}{100}\)
Đúng thì k nha bn !!!!
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\(a,\frac{26}{60}+\frac{3}{15}=\frac{13}{30}+\frac{1}{5}=\frac{13}{30}+\frac{6}{30}=\frac{19}{30}\)
\(b,\frac{4}{26}+\frac{33}{78}=\frac{2}{13}+\frac{11}{26}=\frac{4}{26}+\frac{11}{26}=\frac{15}{26}\)
\(c,\frac{25}{40}-\frac{3}{12}=\frac{5}{8}-\frac{1}{4}=\frac{5}{8}-\frac{2}{8}=\frac{3}{8}\)
\(d,\frac{21}{27}+\frac{10}{54}+\frac{5}{15}=\frac{7}{9}+\frac{5}{27}+\frac{1}{3}=\frac{21}{27}+\frac{5}{27}+\frac{9}{27}=\frac{35}{27}\)
~Study well~
#Thạc_Trân
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\(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}\)
\(=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\)
\(=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\right)\)
\(=1+\frac{28}{5}\)
\(=\frac{33}{5}\)
Ta có:
a) \(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{9}{15}=1+1+\frac{9}{15}=1\frac{9}{15}\)
b)\(\frac{10}{18}+\frac{4}{9}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{16}{128}+\frac{8}{128}+\frac{4}{128}+\frac{2}{128}+\frac{1}{128}\right)\)
\(=1+\frac{31}{128}=1\frac{31}{128}\)
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A/ \(\frac{x}{17}=\frac{60}{204}\)
\(204x=60.17\)
\(204x=1020\)
\(x=\frac{1020}{204}\)
\(x=\frac{17}{4}=4,25\)
vậy x= 4,25
B/ \(\left(6+x\right).11=33.7\)
\(66+11x=231\)
\(11x=231-66=165\)
\(x=\frac{165}{11}\)
\(x=15\)
vậy x = 15
C/ \(\left(12+x\right).3=\left(43-x\right).2\)
\(36+3x=86-2x\)
\(3x+2x=86-36\)
\(5x=50\)
\(x=\frac{50}{5}=10\)
vậy x=10
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\(S=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{90}+\frac{1}{100}\)
\(S=\left(\frac{1}{6}+\frac{1}{12}\right)+\left(\frac{1}{20}+\frac{1}{100}\right)+\left(\frac{1}{30}+\frac{1}{90}\right)\)
\(S=\left(\frac{2}{12}+\frac{1}{12}\right)+\left(\frac{5}{100}+\frac{1}{100}\right)+\left(\frac{3}{90}+\frac{1}{90}\right)\)
\(S=\frac{3}{12}+\frac{6}{100}+\frac{4}{90}\)
\(S=\frac{1}{4}+\frac{3}{50}+\frac{2}{45}\)
\(S=\frac{319}{900}\)
S=\(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.15}+..\)
\(S=SAI\)
HÌNH NHƯ SAI RỒI
HÌNH NHỨIA
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TL :
a) 8,2
b) 36,23
c) 54,07
d) 12,254
Chúc bn hok tốt ~
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\(a,\frac{57}{300}=\frac{19}{100}=19\%\)
\(b,\frac{24}{400}=\frac{6}{100}=6\%\)
\(c,\frac{12}{500}=\frac{2.4}{100}=2,4\%\)
\(d,\frac{750}{600}=\frac{125}{100}=125\%\)
~Study well~
#๖ۣۜNamiko#
GIẢI
a) \(\frac{57}{300}=\frac{19}{100}=19\%\)
b) \(\frac{24}{400}=\frac{6}{100}=6\%\)
c)\(\frac{12}{500}=\frac{6}{250}=2,4\%\)
d )\(\frac{750}{600}=\frac{125}{100}=125\%\)
P/S: HOK TỐT !
\(\frac{12}{60}\)=\(\frac{20}{100}\)
K nhé MN?
~Hok tốt~
\(\frac{12}{60}=\frac{20}{100}\)