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a) -23 + 176 - (2176 - 23)
= -23 + 176 - 2176 + 23
= (-23 + 23) + (176 - 2176)
= 0 + (-2000)
= -2000
b) 125 . (-24) + 24 . 225
= (-125) . 24 + 24 . 225
= 24 . (-125 + 225)
= 24 . 100
= 2400
(15×15×15/16×16×16 + 179/1710)×(1500/1600 -176/187)
=(15/16 + 1/17) × (15/16 - 16/17)
=(15/16 + 1/17) × (15/16 + (-16/17))
=15/16×(1/17+(-16/17))
=15/16 × (-15/17)
=-225/272
\(A=\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}+...+\frac{1}{9700}\)
\(A=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{97.100}\)
\(A=\frac{3}{3}\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{97.100}\right)\)
\(A=\frac{1}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{97.100}\right)\)
\(A=\frac{1}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{97}-\frac{1}{100}\right)\)
\(A=\frac{1}{3}\left(1-\frac{1}{100}\right)\)
\(A=\frac{1}{3}.\frac{99}{100}=\frac{33}{100}\)
\(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}+...+\frac{1}{9700}\)
\(=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{97.100}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{97}-\frac{1}{100}\)
\(=\frac{1}{1}-\frac{1}{100}\)
\(=\frac{100}{100}-\frac{1}{100}\)
\(=\frac{99}{100}\)
a)\(\frac{25}{10}=\frac{50}{20};\frac{-70}{147}=\frac{-140}{294};\frac{-27}{-54}=\frac{54}{108}\)
b)\(\frac{130}{150}=\frac{260}{300};\frac{17}{-10}=\frac{-34}{20};\frac{-56}{21}=\frac{-112}{42}\)
thấy đề bài hơi lạ. Học tốt
\(\frac{-187}{70}+2=\frac{47}{70}\)
\(\Rightarrow\frac{-187}{70}=-2\frac{47}{70}\)
.
\(\frac{-187}{70}=-2\frac{47}{70}\)