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- Ta có : `6/25=(6.5)/(25.5)=30/125`
`14/125<30/125`
`=> 14/125<6/25`
c: 2/5(1/2+3/2)^2=2/5*2^2=2/5*4=8/5
a: 6^100=2^100*3^100
b: 125^22=5^66
a, 119 + 24 + 81
= ( 119 + 81 ) + 24
= 200 + 24
= 224
b, 16 . 6 . 125
= 16 . 125 . 6
= 2000 . 6
= 12000
c, 25 . 104
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d, 12 . 19 + 12
= 12 . 19 + 12 . 1
= 12 . ( 19 + 1 )
= 12 x 20
= 240
e, 43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93 ) + ( 61 + 59 ) . 57
= 43 . 120 + 120 . 57
= 120 . 43 + 120 . 57
= 120 . ( 43 + 57 )
= 120 . 100
= 12000
a/ 199 + 24 + 81
= (119+81) + 24
= 200 + 24
= 224
b/ 16 . 6 . 125
= ( 16 . 125) . 6
= 2000 . 6
= 12000
c/ 25 . 104
= 25 . ( 100 + 4 )
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d/43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93) + 57 . ( 61+ 59)
= 43 . 130 + 57 . 130
= (43 + 57) . 130
= 100 . 130
= 1300
\(P=\dfrac{32}{64}\cdot\dfrac{-57}{19}+\dfrac{35}{21}\cdot\dfrac{22}{44}=\dfrac{1}{2}\left(-3+\dfrac{5}{3}\right)=\dfrac{1}{2}\cdot\dfrac{-4}{3}=\dfrac{-2}{3}\)
\(Q=\dfrac{75}{125}\cdot\dfrac{82}{164}+\dfrac{49}{98}\cdot\dfrac{-35}{105}=\dfrac{1}{2}\left(\dfrac{3}{5}-\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\dfrac{4}{15}=\dfrac{2}{15}\)
\(\dfrac{{21}}{{10}} = 2,1;\dfrac{{ - 35}}{{10}} = - 3,5;\dfrac{{ - 125}}{{100}} = - 1,25;\)\(\dfrac{{ - 89}}{{1000}} = - 0,089\)
\(=\dfrac{5}{4}\cdot\dfrac{1}{4}:\left(\dfrac{21}{16}-\dfrac{24}{16}\right)+1=\dfrac{5}{16}\cdot\dfrac{16}{-3}+1=\dfrac{-5}{3}+1=-\dfrac{2}{3}\)
\(125\%\cdot\left(-\dfrac{1}{2}\right)^2:\left(1\dfrac{5}{16}-1,5\right)+2018^0\)
\(=\dfrac{5}{4}\cdot\dfrac{1}{4}:\left(\dfrac{21}{16}-\dfrac{3}{2}\right)+1\)
\(=\dfrac{5}{16}:\left(-\dfrac{3}{16}\right)+1\)
\(=\dfrac{5}{16}\cdot\left(-\dfrac{16}{3}\right)+1\)
\(=-\dfrac{5}{3}+1\)
\(=-\dfrac{5}{3}+\dfrac{3}{3}\)
\(=-\dfrac{2}{3}\)
`125%*( (-1)/2 )^2 :(1 5/16 -1,5 )+2018^0`
`=1,25 * 1/4 :(21/16-3/2)+1`
`=1,25*1/4:(21/16-24/16)+1`
`=1,25*1/4:(-3)/16+1`
`=5/16*16/(-3)+1`
`=-5/3+1`
`=-5/3+3/3`
`=-2/3`
1) \(\dfrac{17}{5}\cdot\dfrac{-31}{125}\cdot\dfrac{1}{2}\cdot\dfrac{10}{17}\cdot\dfrac{-1}{2^3}\)
\(=\dfrac{17\cdot\left(-31\right)\cdot1\cdot2\cdot5\cdot\left(-1\right)}{5\cdot125\cdot2\cdot17\cdot8}\)
\(=\dfrac{\left(-31\right)\left(-1\right)}{125\cdot8}\\ =\dfrac{31}{1000}\)
\(=125\left(\dfrac{1}{93}+\dfrac{1}{43}\right)=125\cdot\dfrac{136}{3999}=\dfrac{17000}{3999}\)