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14 tháng 2 2016

ủng hộ mik nên 40 điểm nha

cái này là toán lóp 7 ak??lóp 6 chứ

S = ( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + ... + ( 2001 + 2001 - 2003 - 2004 ) + ( 2005 + 2006 )

S = ( - 4 ) + ( - 4 ) + .... + ( - 4 ) + ( 2005 + 2006 )

Dãy S có : 2004 - 1 : 1 + 1 = 2004 số hạng

Dãy số S : 2004 : 4  = 501 số ( - 4 )

Dãy đó S = -4 x 501 = -2004 

S = -2004 + ( 2005 + 2006 ) 

S = -2004 + 4011

S = 2007

15 tháng 10 2016

a)2004100+200499=200499(2004+1)=201499.2005

=>201499.2005chia hết cho 2005

=> 2004100+200499 chia hết cho 2005

b) 413+325-88

=(22)13+(25)5-(23)8

=226+225-224

=224(22+2-1)

=225.5

=>225chia hết cho 5 => 413+325-88 chia hết cho 5

25 tháng 2 2023

Ta có : \(\dfrac{x-2012}{8}+\dfrac{x-2008}{6}+\dfrac{x-2005}{5}=10-\dfrac{x-2004}{4}\)

\(\Leftrightarrow\left(\dfrac{x-2012}{8}-1\right)+\left(\dfrac{x-2008}{6}-2\right)+\left(\dfrac{x-2005}{5}-3\right)+\left(\dfrac{x-2004}{4}-4\right)=0\)\(\Leftrightarrow\dfrac{x-2020}{8}+\dfrac{x-2020}{6}+\dfrac{x-2020}{5}+\dfrac{x-2020}{4}=0\)

\(\Leftrightarrow\left(x-2020\right).\left(\dfrac{1}{8}+\dfrac{1}{6}+\dfrac{1}{5}+\dfrac{1}{4}\right)=0\)

\(\Leftrightarrow x-2020=0\Leftrightarrow x=2020\)

Vậy x = 2020

27 tháng 6 2015

a)2004100+200499=200499(2004+1)=201499.2005

=>201499.2005chia hết cho 2005

=> 2004100+200499 chia hết cho 2005

b) 413+325-88

=(22)13+(25)5-(23)8

=226+225-224

=224(22+2-1)

=225.5

=>225chia hết cho 5

=> 413+325-88 chia hết cho 5

19 tháng 11 2017

8^7 - 2^18
= 2^21 - 2^18
= 2^18 ( 8 - 1)
= 2^17 . 14 chia hết cho 14
=> 8^7 - 2^18 chia hết cho 14

5 tháng 8 2017

\(\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}=\dfrac{x-5}{2004}+\dfrac{x-4}{2005}+\dfrac{x-3}{2006}\)

\(\Leftrightarrow\left(\dfrac{x-8}{2001}+1\right)+\left(\dfrac{x-7}{2002}+1\right)+\left(\dfrac{x-6}{2003}+1\right)=\left(\dfrac{x-5}{2004}+1\right)+\left(\dfrac{x-4}{2005}+1\right)+\left(\dfrac{x-3}{2006}+1\right)\)

\(\Leftrightarrow\dfrac{x-2009}{2001}+\dfrac{x-2009}{2002}+\dfrac{x-2009}{2003}-\dfrac{x-2009}{2004}-\dfrac{x-2009}{2005}-\dfrac{x-2009}{2006}=0\)

\(\Leftrightarrow\left(x-2009\right).\left(\dfrac{1}{2001}+\dfrac{1}{2002}+\dfrac{1}{2003}-\dfrac{1}{2004}-\dfrac{1}{2005}-\dfrac{1}{2006}\right)=0\)

\(\text{Mà}:\left(\dfrac{1}{2001}+\dfrac{1}{2002}+\dfrac{1}{2003}-\dfrac{1}{2004}-\dfrac{1}{2005}-\dfrac{1}{2006}\right)\ne0\)

\(\Rightarrow x-2009=0\Rightarrow x=2009\)

6 tháng 8 2017

\(\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}=\dfrac{x-5}{2004}+\dfrac{x-4}{4}+\dfrac{x-5}{2006}\)

\(\Leftrightarrow\left(\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}\right)-3=\left(\dfrac{x-5}{2004}+\dfrac{x-4}{4}+\dfrac{x-5}{2006}\right)-3\)

\(\Leftrightarrow\left(\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}\right)-\left(1+1+1\right)=\left(\dfrac{x-5}{2004}+\dfrac{x-4}{2005}+\dfrac{x-5}{2006}\right)-\left(1+1+1\right)\)

\(\Leftrightarrow\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}-1-1-1=\dfrac{x-5}{2004}+\dfrac{x-4}{2005}+\dfrac{x-5}{2006}-1-1-1\)

\(\Leftrightarrow\left(\dfrac{x-8}{2001}-1\right)+\left(\dfrac{x-7}{2002}-1\right)+\left(\dfrac{x-6}{2003}-1\right)=\left(\dfrac{x-5}{2004}-1\right)+\left(\dfrac{x-4}{2005}-1\right)+\left(\dfrac{x-5}{2006}-1\right)\)

\(\)\(\Leftrightarrow\dfrac{x-2009}{2001}+\dfrac{x-2009}{2002}+\dfrac{x-2009}{2003}=\dfrac{x-2009}{2004}+\dfrac{x-2009}{2006}+\dfrac{x-2009}{2006}\)

\(\Leftrightarrow\left(\dfrac{x-2009}{2001}+\dfrac{x-2009}{2002}+\dfrac{x-2009}{2003}\right)-\left(\dfrac{x-2009}{2004}+\dfrac{x-2009}{2006}+\dfrac{x-2009}{2006}\right)=0\)

\(\Leftrightarrow\dfrac{x-2009}{2001}+\dfrac{x-2009}{2002}+\dfrac{x-2009}{2003}-\dfrac{x-2009}{2004}-\dfrac{x-2009}{2006}-\dfrac{x-2009}{2006}=0\)

\(\Leftrightarrow\left(x-2009\right)\left(\dfrac{1}{2001}+\dfrac{1}{2002}+\dfrac{1}{2003}-\dfrac{1}{2004}-\dfrac{1}{2005}-\dfrac{1}{2006}\right)=0\)

\(\Leftrightarrow x-2009=0\)

\(\Leftrightarrow x=2009\)

Vậy \(x=2009\)

17 tháng 7 2016

Ta có :

8- 218 = ( 23 )7 - 218= 221 -  218 = 218 ( 23 - 1 ) = 218 . 7 = 217 .2.7 = 217 . 14 ( chia hết cho 14 )

Vậy 87-218chia hết cho 14

17 tháng 7 2016

\(8^7-2^{18}\)\(=\left(2^3\right)^7-2^{18}=2^{21}-2^{18}=2^{17}.2^4-2^{17}.2=2^{17}.\left(2^4-2\right)\)

                       \(=2^{17}.\left(2^4-2\right)=2^{17}.14\)