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gọi biểu thức là A
ta có :
A=3/1.2.3 + 5/2.3.4 + 7/3.4.5 +....+ 2017/1008.1009.1010
A= (1.2/1.2.3 + 2.2/2.3.4 + 3.2/3.4.5 + ... + 1008.2/1008.1009.1010) + (1/1.2.3 + 1/2.3.4 + 1/3.4.5 +...+ 1/1008.1009.1010)
A=(2/2.3 + 2/3.4 + 2/4.5 +...+ 2/1009.1010 + 1/2.(1/1.2-1/2.3+1/2.3-1/3.4+1/3.4-1/4.5 + ... + 1/1008.1009 - 1/1009.1010
A=2(1/2-1/3+1/3-1/4+1/4-1/5+...+1/1009-1/1010)+1/2.(1/2-1/1009.1/1010)
A<2.1/2 + 1/2.1/2 = 1+1/4 = 5/4
OK nhớ tk cho mình nhé ( dấu này / là dấu phần nhé) chúc bạn học tốt
Gọi biểu thức là \(A\). Ta có :
\(A=\dfrac{3}{1.2.3}+\dfrac{5}{2.3.4}+\dfrac{7}{3.4.5}+...+\dfrac{2017}{1008.1009.1010}\)
\(A=\left(\dfrac{1.2}{1.2.3}+\dfrac{2.2}{2.3.4}+\dfrac{3.2}{3.4.5}+...+\dfrac{1008.2}{1008.1009.1010}\right)+\left(\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{1008.1009.1010}\right)\)\(A=\left(\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+...+\dfrac{2}{1009.1010}\right)+\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{1008.1009}-\dfrac{1}{1009.1010}\right)\)
\(A=2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{1009}-\dfrac{1}{1010}\right)+\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{1009.1010}\right)\)
\(A< 2.\dfrac{1}{2}+\dfrac{1}{2}.\dfrac{1}{2}=1+\dfrac{1}{4}=\dfrac{5}{4}\)
A) \(A=1+4+4^2+4^3+...+4^{26}\)
\(\Rightarrow4A=4+4^2+4^3+4^4+...+4^{27}\)
\(\Rightarrow4A-A=4^{27}-1\)
\(3A=4^{27}-1\)
\(A=\frac{4^{27}-1}{3}\)
B) \(B=3+3^3+3^5+3^7+...+3^{21}\)
\(\Rightarrow3^2B=3^3+3^5+3^7+3^9+...+3^{23}\)
\(\Rightarrow3^2B-B=3^{23}-3\)
\(8B=3^{23}-3\)
\(B=\frac{3^{23}-3}{8}\)
C) \(M=1.2+2.3+3.4+...+49.50\)
\(\Rightarrow3M=1.2.3+2.3.3+3.4.3+...+49.50.3\)
\(3M=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+49.50.\left(51-48\right)\)
\(3M=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+49.50.51-48.49.50\)
\(3M=\left(1.2.3+2.3.4+3.4.5+...+49.50.51\right)-\left(1.2.3+3.4.5+...+48.49.50\right)\)
\(3M=49.50.51\)
\(M=\left(49.50.51\right):3\)
\(M=41650\)
D) \(N=1.2.3+2.3.4+3.4.5+...+49.50.51\)
\(\Rightarrow4N=1.2.3.4+2.3.4.4+3.4.5.4+...+49.50.51.4\)
\(4N=1.2.3.\left(4-0\right)+2.3.4\left(5-1\right)+3.4.5.\left(6-2\right)+...+49.50.51.\left(52-48\right)\)
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