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1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
\(3\frac{4}{5}=3,8\)
\(2\frac{3}{4}=2,75\)
\(1\frac{12}{25}=1,48\)
HOK TOT
\(\frac{1+2+3+4+5+6+7+8+9}{11+12+13+14+15+16+17+18+19}\)
\(=\frac{\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5}{\left(11+19\right)+\left(12+18\right)+\left(13+17\right)+\left(14+16\right)+15}\)
\(=\frac{10+10+10+10+5}{30+30+30+30+15}\)
\(=\frac{55}{135}=\frac{11}{27}\)\
TK MK NHA
bn tự giải phần b) nha
a) MC: 20
\(\frac{3}{4}\)=\(\frac{3x5}{4x5}\)=\(\frac{15}{20}\)
\(\frac{2}{5}\)=\(\frac{2x4}{5x4}\)=\(\frac{8}{20}\)
b) MC: 36
\(\frac{5}{12}\)=\(\frac{5x3}{12x3}\)=\(\frac{15}{36}\)
\(\frac{11}{36}\)giữ nguyên
c) MC: 60
\(\frac{2}{3}\)=\(\frac{2x20}{3x20}\)=\(\frac{40}{60}\)
\(\frac{3}{4}\)=\(\frac{3x15}{4x15}\)=\(\frac{45}{60}\)
\(\frac{4}{5}\)=\(\frac{4x12}{5x12}\)=\(\frac{48}{60}\)
a ) Ta có :
\(\frac{3}{4}=\frac{3.5}{4.5}=\frac{15}{20}\)
\(\frac{2}{5}=\frac{2.4}{5.4}=\frac{8}{20}\)
1.Chuyển các hỗn số sau thành phân số:
\(2\frac{1}{3}\)= \(\frac{7}{3}\)
\(4\frac{2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{12}{4}\)
\(9\frac{5}{7}=\frac{68}{7}\)
\(10\frac{3}{10}=\frac{103}{10}\)
2.Chuyển các hỗn số thành phân số rồi thực hiện phép tính:
\(\alpha.\)\(2\frac{1}{3}+4\frac{1}{3}=\frac{7}{3}+\frac{13}{3}=\frac{20}{3}\)
b. \(9\frac{2}{7}+5\frac{3}{7}=\frac{65}{7}+\frac{38}{7}=\frac{103}{7}\)
c. \(10\frac{3}{10}+4\frac{7}{10}=\frac{103}{10}+\frac{47}{10}=\frac{150}{10}\)=\(15\)
d. \(2\frac{1}{3}+5\frac{1}{4}=\frac{7}{3}+\frac{21}{4}=\frac{21}{12}+\frac{63}{12}=\frac{84}{12}\)= 7
e. \(3\frac{2}{5}+2\frac{1}{7}=\frac{17}{5}+\frac{15}{7}=\frac{119}{35}+\frac{75}{35}=\frac{194}{35}\)
g. \(8\frac{1}{6}+2\frac{1}{7}=\frac{49}{6}+\frac{15}{7}=\frac{342}{42}+\frac{90}{42}=\frac{432}{42}\)
