Question

[Cô nàng Bạch Dương]

Cho:  \(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}\) và\(2x^3-1=15\).Tìm x+y+z.

Answer 1

[Huỳnh Kim Nhật Thanh]

Ta có:\(2x^3-1=15\Rightarrow x^3=8\Rightarrow x=2\)

\(\frac{y-25}{16}=2\Rightarrow y=2.16+25=57\)

\(\frac{z+9}{25}=2\Rightarrow z=25.2-9=41\)

Answer 2

[Anna]

\(2x^3-1=15\)

\(2x^3=16\)

\(x^3=8\)

\(x=2\)

\(\Rightarrow\frac{x+16}{9}=\frac{2+16}{9}=\frac{18}{9}=2\)

\(\Rightarrow\frac{y-25}{16}=2\)

\(\Rightarrow y-25=32\)

\(\Rightarrow y=57\)

\(\Leftrightarrow\frac{z+9}{25}=2\)

\(\Rightarrow z+9=50\)

\(\Rightarrow z=50-9=41\)

Vậy \(z=41;x=2;y=57\)