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`a)1<3`
`=>1/5<3/5`
`b)21>9`
`=>8/21<8/9`
`c)3/5<5/5=1`
`d)7/5>5/5=1`
Ta có: \(C=5\dfrac{9}{10}:\dfrac{3}{2}-\left(2\dfrac{1}{3}\cdot4\dfrac{1}{2}-2\cdot2\dfrac{1}{3}\right):\dfrac{7}{4}\)
\(=\dfrac{59}{10}\cdot\dfrac{2}{3}-\left(\dfrac{7}{3}\cdot\dfrac{9}{2}-2\cdot\dfrac{7}{3}\right):\dfrac{7}{4}\)
\(=\dfrac{59}{15}-\left(\dfrac{7}{3}\cdot\dfrac{5}{2}\right):\dfrac{7}{4}\)
\(=\dfrac{59}{15}-\dfrac{35}{6}\cdot\dfrac{4}{7}\)
\(=\dfrac{59}{15}-\dfrac{10}{3}\)
\(=\dfrac{3}{5}\)
\(\dfrac{3}{5}\) x \(\dfrac{1}{7}\) x 1\(\dfrac{1}{2}\)
= \(\dfrac{3}{35}\) x \(\dfrac{3}{2}\)
= \(\dfrac{9}{70}\)
a) \(1\frac{1}{2}+1\frac{1}{3}=\left(1+1\right)\frac{1}{2}+\frac{1}{3}=2+\frac{5}{6}=2\frac{5}{6}\)
b) \(2\frac{2}{3}-1\frac{4}{7}=\left(2-1\right)\frac{2}{3}-\frac{4}{7}=1+\frac{2}{21}=1\frac{2}{21}\)
c) \(2\frac{2}{3}\times5\frac{1}{4}=\frac{8}{3}\times\frac{21}{4}=14\)
d) \(3\frac{1}{2}:2\frac{1}{4}=\frac{7}{2}:\frac{9}{4}=\frac{7}{2}\times\frac{4}{9}=\frac{14}{9}\)
a) \(1\frac{1}{2}+1\frac{1}{3}=\frac{3}{2}+\frac{4}{3}=\frac{17}{6}\)
b) \(2\frac{2}{3}-1\frac{4}{7}=\frac{8}{3}-\frac{11}{4}=\frac{23}{21}\)
c) \(2\frac{2}{3}\times5\frac{1}{4}=\frac{8}{3}\times\frac{21}{4}=14\)
d) \(3\frac{1}{2}\div2\frac{1}{4}=\frac{7}{2}\div\frac{9}{4}=\frac{14}{9}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
1/2 lít = nửa lít = 1 cốc
Người ta đã rót số cốc nước cam như thế là :
3 x 2 + 1 = 7 ( cốc )
Đ/s : ......
C=1/(2x4)+1/(4x6)+...+1/(18x20)
2C=2/(2x4)+2/(4x6)+...+2/(18x20)
2C=1/2-1/4+1/4-1/6+....-1/20
2C= 1/2- 1/20
2C= 9/20
C= 9/20 x 1/2
C= 9/40
- Quên k auto súc vặc
\(\frac{21}{??}\)x 3 = \(2\frac{1}{3}\)
\(\frac{21}{??}\)=\(\frac{7}{3}\):3 = 7
=>\(\frac{21}{??}\)=7 => ??=21:7=3