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11/12-(5/42-x)=-(15-11/13)
=>11/13-(5/42-x)=184/13
=>5/42-x=11/13- (-184/13)
=>5/42-x=15
=>x=5/42-15
=>x=-625/42
5/42-x=11/13- [-(15-11/13)]=11/13+15-11/13
5/42-x=(11/13-11/13)+15=15
x=5/42-15=5/42-630/42
x=-625/42
Vậy x=-625/42
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a/ ( 35-x)-25=40-(15-18)
(35-x)-25=40-(-3)
(35-x)-25=43
35-x=43+25
35-x=68
x=35-68
x= -33
b/ x+42=-15+27: 3^2
x+42=-15+27 : 9
x+42=-15+3
x+42=-12
x=-12 -42
x= -54
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<=> 126 - 3x + 15 = 8 x 3 x 5
<=> 3x = 126 + 15 - 8 x 3 x 5
<=> 3x = 21
<=> x = 7
[3 (42-X )+15]÷5=2^3×3
[3 (42-x )+15]÷5=8×3
[3 (42-x )+15]÷5=24
3 (42-x )+15=24×5
3 (42-x )+15=120
3 (42-x )=120-15
3 (42-x )=105
42-x=105÷3
42-x=35
x=42-35
x=7
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a) \(x⋮15;x⋮35;x⋮42\&250< x< 850\) (sửa dấu chia thành chia hết)
\(BCNN\left(15;35;42\right)=210\)
\(\Rightarrow x\in BC\left(15;35;42\right)=\left\{0;210;420;630;840;...\right\}\)
mà \(250< x< 850\)
\(\Rightarrow x\in\left\{420;630;840\right\}\)
b) x nhỏ nhất khác 0 thỏa mãn \(x⋮15;x⋮115\)
\(BCNN\left(15;115\right)=345\)
Vậy \(x\in\left\{345\right\}\) thỏa mãn đề bài
\(\left(-15\right)+x=-42\)
\(x=\left(-42\right)-\left(-15\right)\)
\(x=-27\)