\(^2\) - 10x + 5 - 20y
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24 tháng 7 2020

thungan nguyen: không có gì :)

24 tháng 7 2020

a) 5x22 - 10x + 5 - 20y2 2

= 5(x2 - 2x + 1 - 4y2)

= 5[(x - 1)2 - 4y2]

= 5(x - 1 - 2y)(x - 1 + 2y)

b) 8a3 + 2a - 18ab4 - 8a2

= 2a(4a2 + 1 - 9b4 - 4a)

= 2a(4a2 - 4a + 1 - 9b4)

= 2a[(2a - 1)2 - 9b4]

= 2a(2a - 1 - 3b2)(2a - 1 + 3b2)

9 tháng 3 2019

\(a^4+8a^3+14a^2-8a-15\)

\(=a^4+8a^3+15a^2-a^2-8a-15\)

\(=a^2\left(a^2+8a+15\right)-\left(a^2+8a+15\right)\)

\(=\left(a^2+8a+15\right)\left(a^2-1\right)\)

\(=\left(a+3\right)\left(a+5\right)\left(a-1\right)\left(a+1\right)\)

24 tháng 9 2020

a) 4a2b3 - 6a3b2 = 2a2b2( 2b - 3a )

b) ( a - b )2 - ( b - a ) = ( a - b )2 + ( a - b ) = ( a - b )( a - b + 1 )

c) ( 8a3 - 27b3 ) - 2a( 4a2 - 9b2 ) = 8a3 - 27b3 - 8a3 + 18ab2 = 18ab2 - 27b3 = 9b2( 2a - 3b )

d) 10x2 + 10xy + 5x + 5y = 10x( x + y ) + 5( x + y ) = ( x + y )( 10x + 5 ) = 5( x + y )( 2x + 1 )

e) 5ay - 3bx + ax - 15by = 5y( a - 3b ) + x( a - 3b ) = ( a - 3b )( 5y + x )

24 tháng 9 2020

a) \(4a^2.b^3-6a^3.b^2=2a^2.b^2\left(2b-3a\right)\)

b) \(\left(a-b\right)^2-\left(b-a\right)=\left(a-b\right)^2+\left(a-b\right)\)

\(=\left(a-b\right).\left(a-b+1\right)\)

c) \(8a^3-27b^3-2a.\left(4a^2-9b^2\right)=8a^3-27b^3-8a^3+18ab^2\)

\(=-27b^3+18ab^2=18ab^2-27b^3=9b^2.\left(2a-3b\right)\)

d) \(10x^2+10xy+5x+5y=5.\left(2x^2+2xy+x+y\right)\)

\(=5.\left[\left(2x^2+2xy\right)+\left(x+y\right)\right]=5.\left[2x\left(x+y\right)+\left(x+y\right)\right]\)

\(=5\left(x+y\right)\left(2y+1\right)\)

e) \(5ay-3bx+ax-15by=\left(5ay-15by\right)-\left(3bx-ax\right)\)

\(=5y\left(a-3b\right)-x\left(3b-a\right)=5y\left(a-3b\right)+x\left(a-3b\right)\)

\(=\left(a-3b\right)\left(x+5y\right)\)

21 tháng 10 2019

\(a,x\left(x^2+4x+4\right)=x\left(x+2\right)^2\)

\(b,x\left(y+1\right)+y+1=\left(x+1\right)\left(y+1\right)\)

\(c,\left(x+y\right)^2-9z^2=\left(x+y-3z\right)\left(x+y+3z\right)\)

\(d,5\left(x^2-2x+1-y^2\right)=5\left(\left(x+1\right)^2-y^2\right)=5\left(x+1-y\right)\left(x+1+y\right)\)

29 tháng 10 2016

a, 8x2+10x =2x.(4x+5)

b, 4x2-8x+4 =4.(x2 -2x+1)=4.(x-1)2

c, 3x2 -3xy -5x +5y =(3x2-5x) - (3xy-5y) = x.(3x-5)- y.(3x-5)= (x-y).(3x-5)

d, x2+ 4x- 45=x2+ 9x- 5x- 45= x.(x+9)- 5.(x+9)=(x-5).(x+9)

29 tháng 10 2016

a , 8 x 2 + 10 x

= 2 x ( 4 x + 5 )

b , 4 x 2 - 8 x + 4

= ( 2x ) 2 - 2 . 2 x . 2 + 2 2

= ( 2x + 2 ) 2

c ) 3 x 2 - 3 x y - 5 x + 5 y

= 3 x ( x - y ) - 5 ( x - y )

= ( 3x - 5 ) ( x - y )

d ) x 2 + 4x - 45

= x 2 + 2 x . 2 + 4 - 49

= ( x + 2 ) 2 - 49

= ( x + 2 ) 2 - 7 2

= ( x + 2 - 7 ) ( x + 2 + 7)

= ( x - 5 ) ( x + 9 )

18 tháng 9 2020

27x6 + 125y6 = ( 3x2 )3 + ( 5y2 )3 = ( 3x2 + 5y2 )( 9x4 - 15x2y2 + 25y4 )

8a6 - 8b6 = ( 2a2 )3 - ( 2b2 )3 = ( 2a - 2b )( 4a2 + 4ab + 4b2 ) = 2( a - b )4( a2 + ab + b2 ) = 8( a - b )( a2 + ab + b2 )

x4 + 64y4 = x4 + 16x2y2 + 64y4 - 16x2y2 

                = ( x4 + 16x2y2 + 64y4 ) - 16x2y2

                = ( x2 + 8y2 )2 - ( 4xy )2

                = ( x2 + 8y2 - 4xy )( x2 + 8y2 + 4xy )

x4 + x3 + 2x2 + x + 1 = x4 + x3 + x2 + x2 + x + 1

                                  = ( x4 + x3 + x2 ) + ( x2 + x + 1 )

                                  = x2( x2 + x + 1 ) + ( x2 + x + 1 )

                                  = ( x2 + x + 1 )( x2 + 1 )

\(27x^6+125y^6=\left(3x^2\right)^3+\left(5y^2\right)^3=\left(3x^2+5y^2\right)\left(9x^4-15x^2.y^2+25y^4\right)\)

\(8a^6-8b^6=8\left(a^6-b^6\right)=8\left(\left(a^3\right)^2-\left(b^3\right)^2\right)=8\left(a^3-b^3\right)\left(a^3+b^3\right)\)

                                                       \(=8\left(a-b\right)\left(a^2+ab+b^2\right)\left(a+b\right)\left(a^2-ab+b^2\right)\)

\(x^{\text{4}}+64y^4=x^4+64y^4+16x^2y^2-16x^2y^2\)

                       \(=\left(8y^2+x^2\right)^2-\left(4xy\right)^2=\left(8y^2+x^2+4xy\right)\left(8y^2+x^2-4xy\right)\)

\(x^4+x^3+2x^2+x+1=\left(x^4+2x^2+1\right)+\left(x^3+x\right)\)

\(=\left(x^2+1\right)^2+x\left(x^2+1\right)=\left(x^2+1\right)\left(x^2+x+1\right)\)

a) \(x^2-2x-15\)

\(\Leftrightarrow x^2-2x+1-16\)

\(\Leftrightarrow\left(x-1\right)^2-4^2\)

\(\Leftrightarrow\left(x-5\right)\left(x-3\right)\)

1 tháng 11 2018

\(a,x^2-2x-15=\left(x^2-2x+1\right)-16.\)

\(=\left(x-1\right)^2-4^2\)

\(=\left(x-5\right)\left(x+3\right)\)

Câu 2 nha

\(a,x^4+2x^3+x^2\)

\(=x^2\left(x^2+2x+1\right)\)

\(=x^2\left(x+1\right)^2\)

\(c,x^2-x+3x^2y+3xy^2+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)

31 tháng 8 2020

a) \(8a^2xy-18b^2xy=2xy\left(4a^2-9b^2\right)=2xy\left(2a-3b\right)\left(2a+3b\right)\)

b) \(32a^2b^2-4=4\left(8a^2b^2-1\right)\)

c) \(x^2-49z^2-4xy+4y^2=\left(x^2-4xy+4y^2\right)-49z^2\)

\(=\left(x-2y\right)^2-\left(7z\right)^2=\left(x-2y+7z\right)\left(x-2y-7z\right)\)

d) \(3x^2+6x+3-3y^2=3\left(x^2+2x+1-y^2\right)=3.\left[\left(x+1\right)^2-y^2\right]\)

\(=3\left(x-y+1\right)\left(x+y+1\right)\)

e) \(12x^2y-12y^3+36xy+27y=3y\left(4x^2-4y^2+12x+9\right)\)

\(=3y\left[\left(4x^2+12x+9\right)-4y^2\right]=3y\left[\left(2x+3\right)^2-\left(2y\right)^2\right]\)

\(=3y\left(2x-2y+3\right)\left(2x+2y+3\right)\)

31 tháng 8 2020

a) 8a2xy - 18b2xy 

= 2xy( 4a2 - 9b2 )

= 2xy( [ ( 2a )2 - ( 3b )2 ]

= 2xy( 2a - 3b )( 2a + 3b )

b) 32a2b2 - 4

= 4( 8a2b2 - 1 )

c) x2 - 49z2 - 4xy + 4y2

= ( x2 - 4xy + 4y2 ) - 49z2

= ( x - 2y )2 - ( 7z )2

= ( x - 2y - 7z )( x - 2y + 7z )

d) 3x2 + 6x + 3 - 3y2

= 3( x2 + 2x + 1 - y2 )

= 3[ ( x2 + 2x + 1 ) - y2 ]

= 3[ ( x + 1 )2 - y2 ]

= 3( x - y + 1 )( x + y + 1 )

e) 12x2y - 12y3 + 36xy + 27y

= 3y( 4x2 - 4y2 + 12x + 9 )

= 3y[ ( 4x2 + 12x + 9 ) - 4y2 ]

= 3y[ ( 2x + 3 )2 - ( 2y )2 ]

= 3y( 2x - 2y + 3 )( 2x + 2y + 3 )

27 tháng 10 2021

helpppppp