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a)\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{3}{7}.\dfrac{-2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\dfrac{-3}{5}\)
=\(\dfrac{-2}{5}.1+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{5}{5}\) = -1
\(\dfrac{5}{9}.\dfrac{14}{17}+\dfrac{1}{17}.\dfrac{5}{9}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\left(\dfrac{14}{17}+\dfrac{1}{17}\right)+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\dfrac{15}{17}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{25}{51}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{691}{612}\)
1b)\(\frac{7}{19}x\frac{8}{11}+\frac{3}{11}:\frac{19}{7}-\frac{2}{-19}=\frac{7}{19}x\frac{8}{11}+\frac{3}{11}x\frac{7}{19}+\frac{2}{19}=\left(\frac{8}{11}+\frac{3}{11}\right)\frac{7}{19}+\frac{2}{19}=\frac{7}{19}+\frac{2}{19}=\frac{9}{19}\)
c)\(4\left(\frac{4}{9}+\frac{7}{11}-\frac{4}{9}\right)=4\frac{7}{11}\)
từ rồi làm tiếp
Tính một cách hợp lí (nếu có thể):
A= -25.(35+147)+35.(25+147)
B=125.9(-4).(-8).25.7
C=(-3)2+(-5)3:I-5I
A=-25*(35+147)+35(25+147)=-25*35-147*25+35*25+147*35=0+147(35-25)=147*10=1470
B=125.9.-4.-8*25*7=(125*-8)(25*-4)(9*7)=-1000*-100*63=6300000
C=(-3)^2+(-5)^3:|-5|=9+(-5)^3:5=9-5^2=9-25=-16
C= (125.73-125.75):(-25.2)
C= 125.(73-75):-50
C= 125.(-2): -50
C= -250 : -50
C= 5
a,
11+6+(-11)+(-3)
= [11+(-11)]+(6+(-3)]
=0+3
=3
b,
25.7.(-5).(-4).2
=[25.(-4)].[-5.(-2)].7
=-100.10.7
-7000
c,
3.25-7.(-25)
=3.25+7.25
=(3+7).25
=10.250
=250