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\(\frac{\left(315+372\right).3+\left(372+315\right).7}{26.13+74.14}\)
\(=\frac{\left(315+372\right)\left(3+7\right)}{26.13+74.13+74}\)
\(=\frac{687.10}{13\left(26+74\right)+74}\)
\(=\frac{6870}{13.100+74}=\frac{6870}{1300+74}\)
\(=\frac{6870}{1374}\)
\(B=\frac{\left(315+372\right).3+\left(372+315\right).7}{26.13+74.14}=\frac{315.3+372.3+372.7+315.7}{26.13+74.14}=\frac{315.\left(7+3\right)+372.\left(7+3\right)}{26.13+74.14}=\frac{3150+3720}{26.13+74.14}\)
đến đấy bó tay
\(a)\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{-5}{3^2}=\frac{-5}{9}\)
\(b)\frac{-11.13^7}{11^5.13^8}=\frac{-1}{11^4.13}\) (Bạn xem thử xem có sai đề không nhé)
\(c)\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3+1\right)}{2^9.3^{10}}=\frac{2.4}{3}=\frac{8}{3}\)
\(d)\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.4+9\right)}=\frac{8}{20+9}=\frac{8}{29}\)
\(a)\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{-5}{3^2}=\frac{-5}{9}\)
\(b)\frac{\left(-11\right)\cdot13^7}{11^5\cdot13^8}=\frac{-1}{11^4\cdot13}=\frac{-1}{14641\cdot13}=\frac{-1}{190333}\)
\(c)\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\left(3^{10}-3^9\right)}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\cdot2}{2^9\cdot3^{10}}=\frac{2\cdot2}{3}=\frac{4}{3}\)
( 315+372 ) . 3 + ( 372 + 315 )
= (315+315) + (372+372) . 3
= 630 + 744 . 3
= 1374 . 3
= 4122
= [ 687 x 3 + 687 x 7 ] : 26 x 13 + 74 x 14
= [ 687 x ( 3 + 7 ) ] : 26 x 13 + 74 x 14
= [ 687 x 10 ] : 26 x 13 + 74 x 14
= 6870 : 26 x 13 + 74 x 14
= 3435 + 1036
= 4471
\(\frac{\left(315+372\right).3+\left(372+315\right).7}{26.13+74.48}\)
\(=\frac{\left(315+372\right).\left(3+7\right)}{\left(26.13\right)+\left(74.48\right)}\)
\(=\frac{687.10}{39+3552}\)
\(=\frac{6870}{3890}=\frac{687}{389}\)