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c)\(\dfrac{3}{8}\times\dfrac{5}{8}+y=\dfrac{5}{4}\)
\(\dfrac{15}{64}+y=\dfrac{5}{4}\)
\(y=\dfrac{5}{4}-\dfrac{15}{64}\)
\(y=\dfrac{65}{64}\)
d, \(\dfrac{3}{8}+\dfrac{5}{8}\times y=\dfrac{5}{4}\)
\(\dfrac{5}{8}\times y=\dfrac{5}{4}-\dfrac{3}{8}\)
\(\dfrac{5}{8}\times y=\dfrac{7}{8}\)
\(y=\dfrac{7}{8}:\dfrac{5}{8}\)
\(y=\dfrac{7}{5}\)
a, 3/4 x y = 3/5 + 3/10
3/4 x y = 9/10
y = 9/10 : 3/4
y = 6/5
b, 3/5 : y = 3/4 - 2/5
3/5 : y = 7/20
y = 3/5 : 7/20
y = 12/7
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X : 8 x 32 + X : 3 x 18 - X : 5 x 10 = 120
X : (32 :8 ) + X : ( 18 :3 ) - X : ( 10 : 5 )
X = ( 4 +6 -2 )=120
X= 8 = 120
X=120 :8
X = 15
\(x\div8\times32+x\div3\times18-x\div5\times10=120\)
\(x\div\left(8\div32\right)+x\div\left(3\div18\right)-x\div\left(5\div10\right)=120\)
\(x\div\frac{1}{4}+x\div\frac{1}{6}-x\div\frac{1}{2}=120\)
\(x\div\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{2}\right)=120\)
\(x\div\frac{-1}{12}=120\)
\(x=120\times\frac{-1}{12}\)
\(x=-10\)
a)100-9:(372:3.y-1)-14=83
<=>100-9:(124y-1)-14=83
<=>86-9:(124y-1)=83
<=>9:(124y-1)=3
<=>124y-1=3
<=>124y=4
<=>y=\(\frac{1}{31}\approx0,3223\)
b)7260-120:24.y+924=528,3
<=>8184-5y=528,3
<=>5y=7655,7
<=>y=1531,14
c)2000-52:(615:3:y-15)-14=1984
<=>1986-52:(205:y-15)=1984
<=>52:(205:y-15)=2
<=>205:y-15=26
<=>205:y=41
<=>y=5
d)y+y.1/3+5/18=7/18
<=>4/3y=1/9
<=>y=1/12
e)13/15-(5/21+y)7/12=7/10
<=>7/12.(5/21+y)=1/6
<=>5/36+7/12y=1/6
<=>7/12y=1/36
<=>y=1/21\(\approx\)0,4762
h)y+2.y+3.y+...+10.y=49,5
<=>55y=49,5
<=>y=0,9
i)y.(1975/8.9+1885/9.10+1755/10.11+1579/11.12)=1/24
<=>7991,364899y=1/24
<=>y=33/6329161
tích nha mỏi tay quá
bài 1
a, X/Y x 1/5=3/10
X/Y=3/10:1/5
X/Y=3/2
b, 3/4 x X/Y= 6/5
X/Y=3/4:6/5
X/Y=5/8
Bài 2:
a, > b, < c,= d,<
Từ đầu bài ta có: y x 4 + y x 6 - y x 2 = 120
y x (4 + 6 - 2) = 120
y x 8 = 120
y = 120 : 8
Vậy y = 15
y : 8 × 32 + y : 3 × 18 - y : 5 × 10 = 120
y × 4 + y × 6 - y × 2 = 120
y × ( 4 + 6 - 2) = 120
y × 8 = 120
y = 120 : 8
y = 15
Vậy y = 15