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a. 49.51- 49.4 -51.49 -51.4
= -49.4 - 51.4
=4.(-49-51)
=4.-100
=-400
b.71.64 + 32.(-7) -13.32
= 71.64 + 32.(-7-13)
=71.64 + 32.-20
=71.32.2 +32.-20
=32.(71x2-20)
=32. 122
= 3904
c. (11-13)+(15-17)+..+(59-61)
=-2 x 13
=-26
a)
\( 49.(51 - 4) - 51.(49 + 4)\)
\(=49.51-49.4-51.49-51.4\)
\(=49.(51-4-51)-51.4\)
\(=49.(-4)-51.4\)
\(=4.(-49-51)\)
\(=4.(-100)\)
\(=-400\)
b)
\( 71.64 + 32.(-7) - 13.32\)
\(=71.32.2+32.(-7)-13.32\)
\(=142.32+32.(-7)-13.32\)
\(=32.(142-7-13)\)
\(=32.122\)
\(=3904\)
c)
\( 11 + (-13) + 15 + (-17) + ... + 59 + (-61)\)
\(=(-2)+(-2)+...+(-2)\)
\(=(-2).13\)
\(=-26\)
\(\left(128-49\right)+\left(-51-28\right)\)
\(=128-49-51-28\)
\(=\left(128-28\right)-\left(49+51\right)\)
\(=100-100=0\)
a) 128 + 43 + 72 + 57
= ( 128 + 72 ) + ( 43 + 57 )
= 200 + 100
= 300
b) 41 . 51 + 49 . 51
= 51 . ( 41 + 49 )
= 51 . 90
= 4590
=
\(a,\) \(128+43+72+57\)
\(=\left(128+72\right)+\left(43+57\right)\)
\(=200+100\)
\(=300\)
\(b,\) \(41.51+49.51=51.\left(41+49\right)=51.90=4590\)
\(c,\) \(4^7:4^5=4^{7-5}=4^2=16\)
\(d,\) \(2.\left(5.4^2-18\right)\)
\(=2.\left(5.2^4-2.3^2\right)\)
\(=2.2.\left(5.2^3-3^2\right)\)
\(=4.\left(40-9\right)\)
\(=4.31=123\)
1) 39×51+39×49=39x(51+49)=39x100=3900
2. phân tích 100 thành 50 r lm như câu 1
1. = 39 x (51 + 49)
= 39 x 100
= 3900
2. = 50 x 2 x 31 + 100 x 19
= 100 x 31 + 100 x 19
= 100 x (31 + 19)
= 100 x 50
= 5000
a: =(-23+23)+230=230
b: =54(-124+24)=-5400
c: =-927+930=3
d: =(-351+51)+(-74-126)-149=-300-200-149=-649
e: \(=\dfrac{3^3\cdot\left(2^3+2^2+1\right)}{13}=3^3=27\)
\(a,=\left[\left(-23\right)+23\right]+230=0+230=230\\ b,=\left(-124\right).54+24.54\\ =54.\left[\left(-124\right)+24\right]=54.\left(-100\right)=-5400\)
; b) 
;
; d) 
;
Bài 1:
a) Ta có: 49+(11-25)
=49+11-25
=24+11
=35
b) Ta có: \(-8+5\cdot\left(-9\right)\)
\(=-8-45\)
=-53
Bài 2:
a) Ta có: \(x-2=-6+17\)
\(\Leftrightarrow x-2=11\)
hay x=13
Vậy: x=13
b) Ta có: \(x+9=2-17\)
\(\Leftrightarrow x+9=-15\)
hay x=-24
Vậy: x=-24
a) \(4 + \left( { - 7} \right) = - \left( {7 - 4} \right) = - 3\)( Vì 7>4)
b) \(\left( { - 5} \right) + 12 = 12 - 5 = 7\) (Vì 12>5)
c) \(\left( { - 25} \right) + 72 = 72 - 25 = 47\) (Vì 72>25)
d) \(49 + \left( { - 51} \right) = - \left( {51 - 49} \right) = - 2\) (Vì 51>49)
a: \(61\cdot45+61\cdot23-68\cdot51\)
\(=61\left(45+23\right)-68\cdot51\)
\(=68\cdot61-68\cdot51\)
\(=68\left(61-51\right)=68\cdot10=680\)
b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)
\(=75-75+4\cdot8\)
\(=4\cdot8=32\)
c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)
\(=\dfrac{36}{20-30+4^2}\)
\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)
d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)
\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)
f: =49*51-49*4-51*49-51*4
=-49*5-51*4
=-4*100=-400
h: =41(-328+128)
=-41*200
=-8200