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\(-\left(+51\right);-|-39|;-37;0;|-18|;-\left(-19\right);25\)
a)11+11+11+11+11+11+11+11+11=\(11^9\)=99.
b)56+56+12+12+12+20+56+56+56=56+56+56+56+56+56=\(56^6\)=336.
c)\(45^8\)=360.
d)\(12^4\)=48
a)11+11+11+11+11+11+11+11+11=\(11^9\)=99.
b)56+56+12+12+12+20+56+56+56=56+56+56+56+56+56=\(56^6\)=336.
c)\(45^8\)=360.
d)\(12^4\)=48
\(a,-13-\left(-15\right)=-13+15=2\)
\(b,43-\left(56-43\right)+\left(56-12\right)=43-13+44=30+44=74\)
\(c,4^4:2^8+\left[13-\left(-5\right)\right]\cdot\left(-3\right)=256:256+\left(13+5\right)\cdot\left(-3\right)\)\(=1+18\cdot\left(-3\right)=1+\left(-54\right)=-53\)
\(d,135\cdot\left(13-37\right)+37\cdot\left(135-13\right)=135\cdot\left(-24\right)+37\cdot122\)\(=-3240+4514=1274\)
a, -13-(-15)=-13+15=2
b, 43-(56-43)+(56-12)=43-13+44=30+44=74
c, 4^4:2^8+[13-(-5)].(-3)=256:256+(13+5).(-3)=1+18.(-3)=1+(-54)=-53
d, 135.(13-37)+37.(135-13)=135.(-24)+37.122=-3240+4514=1274
a) \(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}+\frac{1}{132}\)
\(=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+\frac{1}{11.12}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}\)
\(=\frac{1}{5}-\frac{1}{12}\)
\(=\frac{12}{60}+\frac{-5}{60}\)
\(=\frac{7}{60}\)
b) \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{97.99}\)
\(=\frac{2}{3}.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{97.99}\right)\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{97}-\frac{1}{99}\)
\(=\frac{1}{3}-\frac{1}{99}\)
\(=\frac{33}{99}-\frac{1}{99}\)
\(=\frac{32}{99}\)
a) \(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+...+\frac{1}{132}=\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{11.12}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-...-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}\)
\(=\frac{1}{5}-\frac{1}{12}=\frac{7}{60}\)
b) \(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-...-\frac{1}{97}+\frac{1}{97}-\frac{1}{99}\)
\(=\frac{1}{3}-\frac{1}{99}=\frac{32}{99}\)
a, ta có:VT=0 \(\Rightarrow56^{56}-56^{56}< 56^{56}-56^{54}\)
b,Ta có:\(27^5.7^{16}=(3^3)^5.7^{16}\)\(\Leftrightarrow3^{15}.7^{16}\)
nhận thấy:\(3^5< 3^{15}\);\(7^{15}< 7^{16}\)
\(\Rightarrow3^5.7^{15}< 27^5.7^{16}\)
Minh cam on ban nha !