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Ta có:\(\frac{1}{3x4}+\frac{2}{4x6}+\frac{3}{6x9}+\frac{4}{9x13}+\frac{5}{13x18}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{18}\)
\(=\frac{1}{3}-\frac{1}{18}=\frac{6}{18}-\frac{1}{18}=\frac{5}{18}\)
đặt \(A=\frac{1}{3.4}+\frac{2}{4.6}+\frac{3}{6.9}+\frac{4}{9.13}+\frac{5}{13.18}\)=\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{18}=\frac{1}{3}-\frac{1}{18}=\frac{5}{18}\)
=>A=5/18
vậy........
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cậu nên rút gọn bớt phần dài thay vào dó bằng ba dấu chấm . cậu cứ yên tâm đi thầy giáo chủ nhiệm lớp tớ bảo lảm kiểu như thế này ko sao đâu . cũng ko bị trừ điểm nữa
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a: =>y-3-(48-48:6-3)=0
=>y-3-48+8+3=0
=>y-40=0
hay y=40
b: =>15x13:(29/3-y)=39
=>29/3-y=5
hay y=14/3
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bn viết đề mk chẳng hỉu gì
câu nào mk hỉu mk lm rùi đây (kq thui)
bài 1:
1, 55 2, 85 3, 1 4, 7/5 5, -17/144 6, 29/12
bài 2:
a,1+3+5+..+97+99 = 49.(99+1) = 49.100 =4900
b, 1+4+7+...+97+100 = 33.(100+1) = 33.101 =3333
c,d: chịu ^^ ><
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B=(4+4^2+4^3)+....+(4^15+4^16+4^17)
=4.(4^0+4^1+4^2)+....+4^15.(4^0+4^1+4^2)
=4.(1+4+16)+....+4^15.(1+4+16)
=4.21+...+4^15.21
21.(4+...+4^15) chia hết cho 17
Do B : 17
=> B : 17 dư 0.
sao 21.(4+...+4^15) lại chia hết cho 17
bạn giải thik kĩ đc ko
![](https://rs.olm.vn/images/avt/0.png?1311)
B=(4+4^2+4^3)+....+(4^15+4^16+4^17)
=4.(4^0+4^1+4^2)+....+4^15.(4^0+4^1+4^2)
=4.(1+4+16)+....+4^15.(1+4+16)
=4.21+...+4^15.21
21.(4+...+4^15) chia hết cho 17
vậy B chia hết cho 17
![](https://rs.olm.vn/images/avt/0.png?1311)
Xét \(B=4+4^2+4^3+...+4^{17}\)
\(B=4+\left(4^2+4^3+4^4+4^5\right)+\left(4^6+4^7+4^8+4^9\right)+...+\left(4^{14}+4^{15}+4^{16}+4^{17}\right)\)
\(B=4+4^2\left(1+4+4^2+4^3\right)+4^6\left(1+4+4^2+4^3\right)+...+4^{14}\left(1+4+4^2+4^3\right)\)
\(B=4+4^2\cdot85+4^6\cdot85+...+4^{14}\cdot85\)
\(B=4+85\left(4^2+4^6+...+4^{14}\right)\)
\(B=4+17\cdot5\left(4^2+4^6+...+4^{14}\right)\)
Mà \(17\cdot5\left(4^2+4^6+...+4^{14}\right)⋮17\)
\(\Rightarrow4+17\cdot5\left(4^2+4^6+...+4^{14}\right)\)chia 17 dư 4
Hay \(B\)chia 17 dư 4 (ĐPCM)
\(B=4+4^2+4^3+4^4+........+4^{17}\)
\(B=4+\left(4^2+4^4\right)+\left(4^3+4^5\right)+...+\left(4^{15}+4^{17}\right)\)
\(B=4+4^2\left(1+4^2\right)+.....+4^{15}\left(1+4^2\right)\)
\(B=4+4^2.17+....+4^{15}.17\)
\(B=4+17.\left(4^2+4^3+...+4^{15}\right)\)
\(\Rightarrow\)\(17.\left(4^2+4^3+...+4^{15}\right)\)\(⋮17\)
\(\Rightarrow B:17\)\(dư\)\(4\)
\(\text{Vậy B chia 17 dư 4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
B=4+42+43+...+459+460
\(\Rightarrow\)B=(4+42+43)+(44+45+46)+...+(458+459+460)
\(\Rightarrow\)B=4(1+4+42)+44(1+4+42)+...+458(1+4+42)
\(\Rightarrow\)B=(1+4+42)(4+44+...+458)
\(\Rightarrow\)B=21(4+44+...+458)
Vì 21 \(⋮\)21
\(\Rightarrow\)21(4+44+...+458) \(⋮\)21
\(\Rightarrow\)4+42+43+...+460 \(⋮\)21
\(\Rightarrow\)B \(⋮\)21 (đpcm)
Trả lời:
B = 4 + 42 + 43 + 44 + ... + 460
B = ( 4 + 42 + 43 ) + ( 44 + 45 + 46 ) + ... + ( 458 + 459 + 460)
B = 4 x ( 1 + 4 + 42 ) + 44 x ( 1 + 4 + 42 ) + ... + 458 x ( 1 + 4 + 42 )
B = (4 + 44 + ... + 458) x ( 1 + 4 + 42 )
B = (4 + 44 + ... + 458) x 21
Vì 21 \(⋮\)21
\(\Rightarrow\)(4 + 44 + ... + 458) x 21 \(⋮\)21
Hay B \(⋮\)21 (đpcm)
Vậy B \(⋮\)21
\(B=\frac{4}{8.13}+\frac{4}{13.18}+\frac{4}{18.23}+...+\frac{4}{253.258}\)
\(B=\frac{4}{5}\left(\frac{1}{8}-\frac{1}{13}+\frac{1}{13}-\frac{1}{18}+\frac{1}{18}-\frac{1}{23}+...+\frac{1}{253}-\frac{1}{258}\right)\)
\(B=\frac{4}{5}\left(\frac{1}{8}-\frac{1}{258}\right)\)
\(B=\frac{4}{5}.\frac{125}{1032}\)
\(B=\frac{25}{258}\)