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3 + 3/5 + 3/25 + 3/125 + 3/625
= 1875/625 + 375/625 + 75/625 + 15/625 + 3/625
= 2250/625 + 90/625 + 3/625
= 2340/625 + 3/625
= 2343/625
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3+3/5+3/25+3/125+3/625= 3/625x(625+125+25+5+1)= 3x781/625=2343/625
chu y: vi 3=3x625/625
3/5=3x125/125x5=3x125/625
3/25=3x25/25x25=3x25/625
3/125=3x5/125x5=3x5/625
3/625=3x1/625
cộng các kết quả trên và đặt 3/625 làm nhân từ chúng ta có kết quả như trên.
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Đặt A=3+3/5+3/25+3/125+3/625=3/5+3/5^1+3/5^2+3/5^3+3/5^4
5A=15+3+3/5^1+3/5^2+3/5^3
5A-A=(15+3+3/5^1+3/5^2+3/5^3)-(3+3/5^1+3/5^2+3/5^3+3/5^4)
4A=15-3/625=9372/625
A=2343/625
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Sao mà mình hỏi bài này từ lâu lắm rồi mà vẫn chưa có bạn nào trả lời nhỉ?
A) \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}\)
2A= \(1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\)
2A-A = \(1-\dfrac{1}{32}\)
A= \(\dfrac{31}{32}\)
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a: \(=\dfrac{\left(\dfrac{1}{2}:\dfrac{1}{2}-\dfrac{1}{4}:\dfrac{1}{4}+\dfrac{1}{8}:\dfrac{1}{8}-\dfrac{1}{10}:\dfrac{1}{10}\right)}{1+2+3+...+2008}\)
=0
c: =8,1*5/3*1875+13,5*625
=13,5(1875+625)
=13,5*2500
=33750
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\(3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\)
\(\Rightarrow\frac{3}{1}\cdot\frac{1}{625}+\frac{3}{5}\cdot\frac{1}{125}+\frac{3}{125}\cdot\frac{1}{5}+\frac{3}{625}\)
\(\Rightarrow\frac{3}{625}+\frac{3}{625}+\frac{3}{625}+\frac{3}{625}\)
\(\Rightarrow\frac{3}{625}\cdot4\)
\(\Rightarrow\frac{12}{625}\)
\(B=1+\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+\dfrac{1}{5^4}+\dfrac{1}{5^5}\\ \dfrac{1}{5}\times B=\dfrac{1}{5}+\dfrac{1}{5^2}+\dfrac{1}{5^3}+\dfrac{1}{5^4}+\dfrac{1}{5^5}+\dfrac{1}{5^6}\\ B-\dfrac{1}{5}\times B=1-\dfrac{1}{5^6}\\ \dfrac{4}{5}\times B=1-\dfrac{1}{5^6}\\ B=\dfrac{1-\dfrac{1}{5^6}}{\dfrac{4}{5}}=\dfrac{5^6-1}{4.5^5}=\dfrac{3906}{3125}\)
5xB=5+1+1/5+1/25+1/125+1/625
4xB=5xB-B=5-1/3125
\(\Rightarrow B=\left(5-\dfrac{3}{3125}\right):4\)