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\(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=12\cdot\dfrac{5}{3}=20\)
\(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\left(-16-\dfrac{2}{7}\right)\cdot\dfrac{5}{3}+\left(28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=12\cdot\dfrac{5}{3}=20\)
\(=\left(-16-\dfrac{2}{7}\right)\cdot\dfrac{5}{3}+\left(28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\)
\(=12\cdot\dfrac{5}{3}=20\)
\(16\frac{2}{7}:\left(-\frac{3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
\(=\frac{114}{7}:\left(-\frac{3}{5}\right)+\frac{198}{7}:\frac{3}{5}\)
\(=-\frac{190}{7}+\frac{330}{7}\)
\(=20\)
\(B=16\frac{2}{7}:\left(\frac{-3}{5}\right)-28\frac{2}{7}:\left(\frac{-3}{5}\right)\)
\(B=\frac{114}{7}\cdot\frac{-5}{3}-\frac{198}{7}\cdot\frac{-5}{3}\)
\(B=\left(\frac{114}{7}-\frac{198}{7}\right)\cdot\frac{-5}{3}\)
\(B=\frac{-84}{7}\cdot\frac{-5}{3}\)
\(B=\frac{420}{21}\)
\(B=20\)
\(B=\dfrac{-5}{3}\left(16+\dfrac{2}{7}-28-\dfrac{2}{7}\right)=-12\cdot\dfrac{-5}{3}=20\)