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LV
1
21 tháng 10 2021
\(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=12\cdot\dfrac{5}{3}=20\)
13 tháng 6 2023
\(A=\dfrac{\left(17+\dfrac{1}{4}-4-\dfrac{3}{16}-13-\dfrac{5}{6}\right)\cdot\left(-\dfrac{4}{7}\right)+\dfrac{27}{4}}{\left(5+\dfrac{2}{7}-5-\dfrac{1}{3}\right):\left(6+\dfrac{2}{3}-4-\dfrac{1}{2}\right)}\)
\(=\dfrac{\dfrac{37}{84}+\dfrac{27}{4}}{-\dfrac{1}{21}:\dfrac{13}{6}}=\dfrac{-1963}{6}\)
MN
11 tháng 11 2018
e)\(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)\)
=\(\left(16\dfrac{2}{7}+28\dfrac{2}{7}\right):\left(-\dfrac{3}{5}\right)\)
=\(\dfrac{312}{7}\)\(:\left(-\dfrac{3}{5}\right)\)
=\(-\dfrac{516}{7}\)
MN
11 tháng 11 2018
a)\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)
=\(\dfrac{7}{8}.\left(\dfrac{1}{6}+\dfrac{2}{5}\right)\)
=\(\dfrac{7}{8}.\)\(\dfrac{17}{30}\)
=\(\dfrac{119}{240}\)
19 tháng 11 2022
a: \(=\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\left(\dfrac{7}{21}+\dfrac{2}{3}\right)-\dfrac{32}{17}=2-\dfrac{32}{17}=\dfrac{2}{17}\)
b: \(=-8\cdot\dfrac{1}{4}:\left(\dfrac{9}{4}-\dfrac{7}{6}\right)=-2:\dfrac{27-14}{12}=\dfrac{-2\cdot12}{13}=-\dfrac{24}{13}\)
c: \(=\dfrac{-5}{3}\left(16+\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{-5}{3}\cdot\left(44+\dfrac{4}{7}\right)\)
=-520/7
20 tháng 12 2022
a: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{3}{2}=\dfrac{9-10+18}{12}=\dfrac{17}{12}\)
b: \(=\left(\dfrac{1}{9}+\dfrac{6}{9}\right)^2-\dfrac{1}{3}=\dfrac{49}{81}-\dfrac{27}{81}=\dfrac{22}{81}\)
c; \(=\dfrac{5}{11}\left(-\dfrac{3}{7}-\dfrac{5}{7}\right)+\dfrac{-8}{7}\cdot\dfrac{6}{11}=\dfrac{-8}{7}\left(\dfrac{5}{11}+\dfrac{6}{11}\right)=-\dfrac{8}{7}\)
d: \(=\dfrac{2^{26}}{2^{15}\cdot2^{12}}=\dfrac{1}{2}\)
TT
5 tháng 10 2017
\(A=16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)-28\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)\)
\(A=\left(16\dfrac{2}{7}-28\dfrac{2}{7}\right):\left(\dfrac{-3}{5}\right)\)
\(A=\left(-12\right):\left(\dfrac{-3}{5}\right)\)
\(A=20\)
\(B=\left(\dfrac{3}{4}\right)^2-\left(\dfrac{7}{8}+3\right)+2.\left|\dfrac{-5}{8}\right|\)
\(B=\dfrac{9}{16}-\dfrac{31}{8}+2.\dfrac{5}{8}\)
\(B=\dfrac{9}{16}-\dfrac{31}{8}+\dfrac{5}{4}\)
\(B=\dfrac{-33}{16}\)
5 tháng 10 2017
\(A=\dfrac{114}{7}:\left(\dfrac{-3}{5}\right)-\dfrac{198}{7}:\left(\dfrac{-3}{5}\right)\)
\(A=\left(\dfrac{114}{7}-\dfrac{198}{7}\right):\dfrac{-3}{5}\)
\(A=-12:\dfrac{-3}{5}\)
\(A=-12.\dfrac{-5}{3}\)
\(A=20\)
\(C=\left(\dfrac{3}{4}\right)^2-\left(\dfrac{7}{8}+3\right)+2.\left|\dfrac{-5}{8}\right|\)
\(C=\dfrac{9}{16}-\left(\dfrac{7}{8}+3\right)+2.\dfrac{5}{8}\)
\(C=\dfrac{9}{16}-\left(\dfrac{7}{8}+\dfrac{24}{8}\right)+2.\dfrac{5}{8}\)
\(C=\dfrac{9}{16}-\dfrac{31}{8}+2.\dfrac{5}{8}\)
\(C=\dfrac{9}{16}-\dfrac{31}{8}+\dfrac{5}{4}\)
\(C=\dfrac{9}{16}-\dfrac{62}{16}+\dfrac{5}{4}\)
\(C=\dfrac{-53}{16}+\dfrac{5}{4}\)
\(C=\dfrac{-53}{16}+\dfrac{20}{16}\)
\(C=\dfrac{-33}{16}\)
NP
1
9 tháng 6 2022
\(=\left(-16-\dfrac{2}{7}\right)\cdot\dfrac{5}{3}+\left(28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\)
\(=12\cdot\dfrac{5}{3}=20\)
KK
21 tháng 12 2018
a)\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)=\dfrac{7}{8}.\left(\dfrac{10}{60}+\dfrac{24}{60}\right)=\dfrac{7}{8}.\dfrac{17}{30}=\dfrac{114}{240}\)
b)\(\dfrac{3}{2}-\dfrac{5}{6}\left(\dfrac{1}{2}\right)^2+\sqrt{4}=\dfrac{3}{2}-\dfrac{5}{6}.\dfrac{1}{4}+2=\dfrac{3}{2}-\dfrac{5}{24}+2=\dfrac{36}{24}-\dfrac{5}{24}+\dfrac{48}{24}=\dfrac{79}{24}\)c)\(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-1\dfrac{15}{17}+\dfrac{2}{3}=\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\left(\dfrac{7}{21}+\dfrac{2}{3}\right)-1\dfrac{15}{17}=1+\left(\dfrac{7}{21}+\dfrac{14}{21}\right)-\dfrac{32}{17}=1+1-\dfrac{32}{17}=2-\dfrac{32}{17}=\dfrac{34}{17}-\dfrac{32}{17}=\dfrac{2}{17}\)d)\(\left(-2\right)^3.\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)=-8.\left(\dfrac{3}{4}-\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)=-8.\dfrac{2}{4}:\left(\dfrac{54}{24}-\dfrac{28}{24}\right)=-8.\dfrac{2}{4}:\dfrac{13}{12}=-4.\dfrac{12}{13}=\dfrac{-48}{13}\)e)\(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)=16\dfrac{2}{7}.\left(-\dfrac{5}{3}\right)+28\dfrac{2}{7}.\left(-\dfrac{5}{3}\right)=\left(16\dfrac{2}{7}+28\dfrac{2}{7}\right).\left(-\dfrac{5}{3}\right)=\left(\dfrac{120}{7}+\dfrac{196}{7}\right).\left(-\dfrac{5}{3}\right)=\dfrac{316}{7}.\left(-\dfrac{5}{3}\right)=-\dfrac{1580}{21}\)
\(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\left(-16-\dfrac{2}{7}\right)\cdot\dfrac{5}{3}+\left(28+\dfrac{2}{7}\right)\cdot\dfrac{5}{3}\)
\(=12\cdot\dfrac{5}{3}=20\)