Câu hỏi của •Iċε ℌαċкεɾ (Čїεℓ*)•

Question

$A=\frac{2009.2010-2}{2008+2008.2010}$$B=\frac{-2009.20102010}{20092009.2010}$So sánh A và B

Edogawa Conan · Accepted Answer

A = $\frac{2009.2010-2}{2008+2008.2010}=\frac{2009.2010-2}{2008.\left(2010+1\right)}=\frac{2009.2010-2}{2008.2011}=\frac{2008.2010+2010-2}{2008.2011}=\frac{2008.2011}{2008.2011}=1$B = $\frac{-2009.20102010}{20092009.2010}=\frac{-2009.10001.2010}{2009.10001.2010}=-1$1 > -1 => A > BCâu trả lời: A = $\frac{2009.2010-2}{2008+2008.2010}=\frac{2009.2010-2}{2008.\left(2010+1\right)}=\frac{2009.2010-2}{2008.2011}=\frac{2008.2010+2010-2}{2008.2011}=\frac{2008.2011}{2008.2011}=1$B = $\frac{-2009.20102010}{20092009.2010}=\frac{-2009.10001.2010}{2009.10001.2010}=-1$1 > -1 => A > B

Kiyotaka Ayanokoji · Answer

Ta có:$A=\frac{2009.2010-2}{2008+2008.2010}$$A=\frac{\left(2008+1\right).2010-2}{2008+2008.2010}$$A=\frac{2008.2010+2010-2}{2008+2008.2010}$$A=\frac{2008.2010+2008}{2008+2008.2010}$$A=1$     $B=\frac{-2009.20102010}{20092009.2010}$$B=\frac{-2009.2010.10001}{2009.10001.2010}$$B=-1$Vì $1>-1\Rightarrow A>B$Vậy $A>B$Câu trả lời: Ta có:$A=\frac{2009.2010-2}{2008+2008.2010}$$A=\frac{\left(2008+1\right).2010-2}{2008+2008.2010}$$A=\frac{2008.2010+2010-2}{2008+2008.2010}$$A=\frac{2008.2010+2008}{2008+2008.2010}$$A=1$     $B=\frac{-2009.20102010}{20092009.2010}$$B=\frac{-2009.2010.10001}{2009.10001.2010}$$B=-1$Vì $1>-1\Rightarrow A>B$Vậy $A>B$

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