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\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)
\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)
c,d tương tự
a ) \(3\frac{4}{5}-2\frac{3}{4}:1\frac{1}{8}=\frac{19}{5}-\frac{11}{4}:\frac{9}{8}=\frac{19}{5}-\frac{22}{9}=\frac{61}{45}\)
b ) \(4\frac{5}{7}:1\frac{5}{6}+2\frac{7}{15}.\frac{21}{74}=\frac{33}{7}:\frac{11}{6}+\frac{37}{15}.\frac{21}{74}=\frac{18}{7}+\frac{7}{10}=\frac{229}{70}\)
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
\(a,8\frac{3}{4}+4\frac{1}{5}-3\frac{3}{4}\)
\(=\frac{35}{4}+\frac{21}{5}-\frac{15}{4}\)
\(=\frac{175+84-75}{20}\)
\(=\frac{184}{20}=\frac{46}{5}\)
\(b,3\frac{1}{2}\div\frac{1}{2}+3\frac{1}{2}\div\frac{1}{4}\)
\(=\frac{7}{2}\div\frac{1}{2}+\frac{7}{2}\div\frac{1}{4}\)
\(=\frac{7}{2}\div\left(\frac{1}{2}+\frac{1}{4}\right)\)
\(=\frac{7}{2}\div\frac{3}{4}\)
\(=\frac{7}{2}\times\frac{4}{3}\)
\(=\frac{14}{3}\)