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a) \(x^2-x=\left(x+1\right).x\)
b) \(5x^2.\left(x-2y\right)-15x.\left(x-2y\right)=\left(x-2y\right).\left(5x^2-15x\right)\)= \(\left(x-2y\right).5x.\left(x-3\right)\)
c) \(3.\left(x-y\right)-5x.\left(y-x\right)=3\left(x-y\right)+5x\left(x-y\right)\)= \(\left(x-y\right).\left(3+5x\right)\)
a) \(x^2-x=x\left(x-1\right)\)
b) \(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)\(=\left(x-2y\right)\left(5x^2-15x\right)\)\(=\left(x-2y\right).5x\left(x-3\right)\)
c) \(3\left(x-y\right)-5x\left(y-x\right)\)\(=3\left(x-y\right)+5x\left(x-y\right)\)\(=\left(3+5x\right)\left(x-y\right)\)
chắc chắn là đúng 100% luôn
thấy đúng thì k nha
a) \(x^2-x\)
\(=x\left(x-1\right)\)
b) \(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)
\(=\left(x-2y\right)\left(5x^2-15x\right)\)
\(=\left(x-2y\right).5x.\left(x-3\right)\)
c) \(3\left(x-y\right)-5x\left(y-x\right)\)
\(=3\left(x-y\right)+5x\left(x-y\right)\)
\(=\left(x-y\right)\left(3+5x\right)\)
a)\(x^2-x=x\left(x-1\right)\)
b)\(5x^2\left(x-2y\right)-15x\left(x-2y\right)=x.5x\left(x-2y\right)-3.5x\left(x-2y\right)=5x\left(x-2y\right)\left(x-3\right)\)
c)\(3\left(x-y\right)-5x\left(y-x\right)=3\left(x-y\right)+5x\left[-\left(y-x\right)\right]=3\left(x-y\right)+5x\left(x-y\right)=\left(x-y\right)\left(3+5x\right)\)
a)\(\left(x-y\right)^2-2\left(x-y\right)+1=\left(x-y-1\right)^2\)
b)\(x^2-2y-1-2x+1-y^2=\left(x^2-2x+1\right)-\left(y^2+2y+1\right)\)
\(=\left(x-1\right)^2-\left(y+1\right)^2\)
\(=\left[\left(x-1\right)-\left(y+1\right)\right]\left[\left(x-1\right)+\left(y+1\right)\right]\)
\(=\left(x-y-2\right)\left(x+y\right)\)
c)\(x^2-y^2-2x-1=x^2-\left(y^2+2x+1\right)\)
\(=x^2-\left(y+1\right)^2\)
\(=\left(x^2-y-1\right)\left(x^2+y+1\right)\)
A. Ta có: (x - y)2 - 2(x - y)+1 = (x - y)2 - 2.(x - y).1 +12 = ( x - y - 1)2
B. Ta có: x2 - 2y -1 - 2x +1 -y2 = (x2 - y2) - (2x - 2y) -1+1 = (x - y)(x + y) - 2(x - y) = (x - y)(x + y - 2)
C. Ta có: x2 - y2 -2y -1 = x2 -(y2 - 2y -1) = x2 - ( y2 +2y1 + 1) = x2 - (y+1)2 = (x - y - 1)(x + y +1)
k cho mình nha bạn hihj!!! ~3~
a/ -8x2 - 12xy3 - 4xy2 = -4x (2x + 3y3 + y2)
b/ (x - y)3 - x3 + y3 = x3 - 3x2y + 3xy2 - y3 - x3 + y3 = -3x2y + 3xy2 = -3xy (x - y)
c/ 3x(x - y) - 2y(x - y) = (x - y) (3x - 2y)
d/ a(x + 2) - 2b(x + 2) + (x + 2) = (x + 2) (a - 2b +1)
e/ 5x(x - y) - (y - x) = 5x(x - y) + (x - y) = (x - y) (5x + 1)
a) =y^2-(x+3)^2
=(y-x-3)(y+x+3).
b)
=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x-y-1)(x+y+1)
c)
=(5x^2-15x)(xy-2y)
=5x(x-3)y(x-2)
=5xy(x-2)(x-3).
2a) \(4x^2-1=\left(2x\right)^2-1^2=\left(2x+1\right)\left(2x-1\right)\)
b) \(x^2+16x+64=\left(x+8\right)^2\)
c) \(x^3-8y^3=x^3-\left(2y\right)^3\)
\(=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\)
d) \(9x^2-12xy+4y^2=\left(3x-2y\right)^2\)
a, x^2-x=x . x -x =x(x-1)
b, 5x^2(x-2y)-15x(x-2y)
=(5x^2-15x)(x-2y)
=5x(x-3)(x-2y)
=5x[x(3-2y)]
c, 3(x-y)-5x(y-x)
=3(x-y)+5x(x-y)
=(3+5x)(x-y)