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a11.62+(-12).11+50.11
=11.(62+(-12)+50)
=11.(50+50)
11.100=1100
b5/13+-5/7+-20/41+8/13+21/41
=(5/13+8/13)+(-20/41+21/41)+-5/7
=1+1/41+-5/7
=89/287
nhớ tích đúng nha
a, 11.62+(-12).11+50.11
= 11.[62+(-12)+50]
= 11.100 = 1100
b, 5/13 + -5/7 + -20/41 + 8/13 + 21/41
= ( 5/13 + 8/13 ) + [ -20/41 + 21/41 ] + -5/7
= 1 + 1/41 + -5/7
= 89/287
dễ, nhưng phai giai dc câu nay 60% nhan x cong 2 phan 3 = 1 phan 3 nhan 6va 1 phan 3
\(\frac{7}{13}.\frac{5}{9}+\frac{7}{19}.\frac{8}{13}-3.\frac{7}{19}=\)\(\frac{-1288}{2223}\)
a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)
= \(\dfrac{12}{20}\) + \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)
= \(\dfrac{39}{20}\)
b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)
= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)
= \(\dfrac{7}{12}\)
cau 1:8/45:8/9-2/5.x=8/45*9/8-2/5.x=8.9/45.8-2/5.x=1/5-2/5.x=2/-3. =>2/5.x=1/5-2/-3=3/15+2/3=3/15+10/15=13/15. =>x=13/15:2/5=13/15.5/2=13.5/15.2=13/6. Vậy x = 13/6. k nha co j ket ban
8/45 : 8/9 - 2/5 . X = 2/-3
8/45 . 9/8 - 2/5 . X = -2/3
1/5 - 2/5 . X = -2/3
-1/5 . X = -2/3
X = -2/3 : -1/5
X = -2/3 x 5/-1 = 10/3
=> x = 10/3
tk ủng hộ nhé !
nếu có sai nhờ anh/ chị / bạn sửa giùm em ạ !!!!!
\(\frac{1}{2}+-\frac{1}{5}+-\frac{5}{7}+\frac{1}{6}-\frac{3}{35}+\frac{1}{3}+\frac{1}{41}=\frac{1}{41}\)
` 5/9 . ( -2/13)+5/9.(-7/13)+(-8/13) = 5/9(-2/13-7/13)-8/13=5/9.(-9/13)-8/13=-5/13-8/13=-13/13=-1 `
lạy má, má vào cái ô trên cùng bên trái của phần gửi câu hỏi sẽ có các kí hiệu toán học
Ý bạn là thế này phải không:
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}\)
\(=1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{200}-2.\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+....+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{99}+\frac{1}{100}+\frac{1}{101}+...+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
=\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
a; 0,2.\(\dfrac{15}{36}\) - (\(\dfrac{2}{5}\) + \(\dfrac{2}{3}\)): 1%
= \(\dfrac{1}{12}\) - \(\dfrac{16}{15}\): \(\dfrac{1}{100}\)
= \(\dfrac{1}{12}\) - \(\dfrac{320}{3}\)
= \(\dfrac{1}{12}\) - \(\dfrac{1280}{12}\)
= - \(\dfrac{1279}{12}\)
b; 75% - 1\(\dfrac{1}{2}\) + 0,5 : \(\dfrac{5}{12}\)
= 0,75 - 1,5 + 1,2
= -0,75 + 1,2
= 0,45
c; 1\(\dfrac{3}{15}.0,75-\left(\dfrac{8}{15}+0,25\right)\).\(\dfrac{24}{47}\)
= \(\dfrac{28}{15}\).0,75 - \(\dfrac{47}{60}\).\(\dfrac{24}{47}\)
= \(\dfrac{7}{5}-\dfrac{2}{5}\)
= 1
d; \(\dfrac{32}{15}\): (-1\(\dfrac{1}{5}\) + 1\(\dfrac{1}{3}\))
= \(\dfrac{32}{15}\): (-\(\dfrac{6}{5}\) + \(\dfrac{4}{3}\))
= \(\dfrac{32}{15}\): \(\dfrac{2}{15}\)
= 16
5/8+3/8÷3/11-10
5/8+3/8×11/3-10
5/8+33/24-10
15/24+33/24-10
48/24-10
48/24-10/1
48/24-240/24
-192/24=4/1