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13 tháng 7 2018

\(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)

\(\Rightarrow5x-3\left\{4x-2\left[4x-15x+6\right]\right\}=182\)

\(\Rightarrow5x-3\left\{4x-2\left[-11x+6\right]\right\}=182\)

\(\Rightarrow5x-3\left\{4x-\left(-22x+12\right)\right\}=182\)

\(\Rightarrow5x-3\left\{4x+22x-12\right\}=182\)

\(\Rightarrow5x-3\left\{26x-12\right\}=182\)

\(\Rightarrow5x-78x+36=182\)

\(\Rightarrow-73x=146\)

\(\Rightarrow x=-2\)

Vậy \(x=-2\)

13 tháng 7 2018

\(5x-3.\left(4x-2.\left(4x-3.\left(5x-2\right)\right)\right)=182\\ \)

\(\Leftrightarrow5x-3.\left(4x-2.\left(4x-15x+6\right)\right)=182\)\(\Leftrightarrow5x-3.\left(4x-2.\left(6-11x\right)\right)=182\)

\(\Leftrightarrow5x-3.\left(4x-12+22x\right)=182\Leftrightarrow5x-3.\left(26x-12\right)=182\)

\(\Leftrightarrow5x-78x+36=182\Leftrightarrow-73x=146\Leftrightarrow x=-2\)

Câu 1: \(x^2+5x=2\left(x+5\right)\)

\(\Leftrightarrow x\left(x+5\right)-2\left(x+5\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-2\right)=0\)

=>x=-5 hoặc x=2

Câu 2: 

Ta có: \(5x^4y^6⋮4x^2y^n\)

=>6-n>=0

hay n<=6

3 tháng 6 2018

1.

a) \(\left\{4x-2\left(x-3\right)-3\left[x-3\left(4-2x\right)+8\right]\right\}.\left(-3x\right)\)

= \(\left[4x-2x+6-3\left(x-12+6x\right)+8\right].\left(-3x\right)\)

\(=\left(4x-2x+6-3x+36-18x+8\right).\left(-3x\right)\)

= \(\left(-19x+50\right).\left(-3x\right)\)

\(=57x^2-150x\)

b) \(5\left(3x^2+4y^3\right)+\left[9\left(2x^2-y^3\right)-2\left(x^2-5y^3\right)\right]\)

\(=15x^2+20y^3+\left(18x^2-9y^3-2x^2+10y^3\right)\)

\(=15x^2+20y^3+16x^2+y^3\)

\(=31x^2+21y^3\)

2.

a) \(5x\left(1-2x\right)-3x\left(x+18\right)=0\)

\(\Rightarrow5x-10x^2-3x^2-54x=0\)

\(\Rightarrow-49x-13x^2=0\)

\(\Rightarrow x\left(-49-13x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{-49}{13}\end{matrix}\right.\)

b)

\(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)

\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)

\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)

\(\Rightarrow5x-12x+24x-90x+36=182\)

\(\Rightarrow-73x-146=0\)

\(\Rightarrow x=-2\)

3 tháng 6 2018

cảm ơn bạnvui

13 tháng 9 2020

\(5x-\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\) 

\(5x-\left[4x-2\left(4x-15x+6\right)\right]=182\) 

\(5x-\left[4x-2\left(-11x+6\right)\right]=182\) 

\(5x-\left(4x+22x-12\right)=182\) 

\(5x-\left(26x-12\right)=182\) 

\(5x-26x+12=182\) 

\(-21x=182-12\) 

\(-21x=170\) 

\(x=-\frac{170}{21}\)

\(\Leftrightarrow5x-3\left\{4x-2\left[4x-15x+6\right]\right\}=182\)

\(\Leftrightarrow5x-3\left\{4x-2\left(-11x+6\right)\right\}=182\)

\(\Leftrightarrow5x-3\left\{4x+22x-12\right\}=182\)

\(\Leftrightarrow5x-3\left(26x-12\right)=182\)

\(\Leftrightarrow5x-78x+36=182\)

=>-73x=146

hay x=-2

16 tháng 8 2020

a)   \(=x^4-x^3-2x^3+2x^2+2x^2-2x-x+1\)

\(=x^3\left(x-1\right)-2x^2\left(x-1\right)+2x\left(x-1\right)-\left(x-1\right)\)

\(=\left(x^3-2x^2+2x-1\right)\left(x-1\right)\)

\(=\left(x^3-x^2-x^2+x+x-1\right)\left(x-1\right)\)

\(=\left(x^2-x+1\right)\left(x-1\right)^2\)

c)

\(=6x^4-12x^3+17x^3-34x^2-4x^2+8x-3x+6\)

\(=6x^3\left(x-2\right)+17x^2\left(x-2\right)-4x\left(x-2\right)-3\left(x-2\right)\)

\(=\left(6x^3+17x^2-4x-3\right)\left(x-2\right)\)

\(=\left(6x^3+18x^2-x^2-3x-x-3\right)\left(x-2\right)\)

\(=\left(6x^2-x-1\right)\left(x+3\right)\left(x-2\right)\)

\(=\left(2x-1\right)\left(3x+1\right)\left(x+3\right)\left(x-2\right)\)

16 tháng 8 2020

b)

\(=x^4+1011x^2+1011+\left(1010x^2-2020x+1010\right)\)

\(=x^4+1011x^2+1011+1010\left(x^2-2x+1\right)\)

\(=x^4+1011x^2+1011+1010\left(x-1\right)^2\)

CÓ:   \(x^4+1010\left(x-1\right)^2+1011x^2\ge0\forall x\)

=>   \(x^4+1010\left(x-1\right)^2+1011x^2+1011\ge1011>0\forall x\)

=> ĐA THỨC b > 0 => Ko ph được thành nhân tử.

9 tháng 6 2016

5x - 3{4x - 2[4x - 3(5x - 2)]} = 5x - 12x + 6[4x - 3(5x - 2)] = -7x + 24x - 18(5x - 2) = 17x - 90x + 36 = -73x + 36 = 182

=> -73x = 182 - 36 = 146 => x = 146 : (-73) = -2

12 tháng 6 2018

5x - 3{4x - 2[4x - 3(5x - 2)]} = 182

<=> 5x - 3[4x - 2(4x - 15x + 6)] = 182

<=> 5x - 3(4x - 8x + 30x - 12) = 182

<=>5x - 3(26x - 12) = 182

<=> 5x - 78x + 36 = 182

<=> - 73x = 182 - 36 = 146

<=> x = \(-\dfrac{146}{73}=-2\)

vậy x = -2

2 tháng 6 2016

5x-3{4x-2[4x-3(5x-2)]}

= 5x - 3.[4x - 2(4x - 15x + 6)]

= 5x - 3.(4x - 8x + 30x - 12)

= 5x - 12x + 24x - 90x + 36

= -73x + 36 = 182

=> -73x = 182 - 36 = 146

=> x = 146 : (-73) = -2

2 tháng 6 2016

\(VT=-\left(73x-36\right)\)

\(\Leftrightarrow-\left(73x-36\right)=182\)

\(\Leftrightarrow36-73x=182\)

\(\Leftrightarrow-73x=182-36\)

\(\Leftrightarrow-73x=146\)

\(\Leftrightarrow x=-2\)

Mình nghĩ là vậy :

5x -3 { 4x - 2 [ 4x - 3 (5x - 2)]} = 182 
<=> 5x -3 { 4x -2 [ 4x - 15x +6 ]} =182 
<=> 5x -3 { 4x -2 [ -11x +6 ]} =182 
<=> 5x -3 { 4x + 22x -12 } = 182 
<=> 5x -3 { 26x -12 } =182 
<=> 5x - 78x + 36 = 182 
<=> -73x = 146 
<=> x= -2

2 tháng 6 2016

\(VT=-\left(73x-36\right)\)

\(\Leftrightarrow-\left(73x-36\right)=182\)

\(\Leftrightarrow36-73x=182\)

\(\Leftrightarrow-73x=182-36\)

\(\Leftrightarrow-73x=146\)

\(\Leftrightarrow x=-2\)